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earnstyle [38]
3 years ago
14

The distance versus time plot for a particular object shows a quadratic relationship. Which column of distance data is possible

for this situation? Time (s) A. Distance (m) B. Distance (m) C. Distance (m) D. Distance (m) E. Distance (m) 0 0 2.00 9.00 ‡ ‡ 1 1.00 4.00 18.00 1.00 1.00 2 4.00 6.00 27.00 0.50 0.25 3 9.00 8.00 36.00 0.33 0.11 4 16.00 10.00 45.00 0.25 0.06 5 25.00 12.00 54.00 0.20 0.04 6 36.00 14.00 63.00 0.16 0.02 column A column B column C column D column E
Physics
2 answers:
Alexxandr [17]3 years ago
6 0

just took the test it is A


aleksklad [387]3 years ago
5 0

Answer: VColumn A

Explanation:

In a quadratic relation , variable y is directly proportional to x^2

distance time have the relationship

d = kt²

or

t = kd²

where k is a fixed number (constant).

column A has the perfect squares

: 1, 4, 9, 16...

Therefore d = kt² with k=1:

t = 0, d = 1 x 0² = 0

t = 1, d = 1 x 1² = 1

t = 2, d = 1 x 2² = 4

t = 3, d = 1 x 3² = 9

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A car is traveling at 120 km/h (75 mph). When applied the braking system can stop the car with a deceleration rate of 9.0 m/s2.
Bumek [7]

Answer:

the number of additional car lengths approximately it takes the sleepy driver to stop compared to the alert driver is 15

Explanation:

Given that;

speed of car V  = 120 km/h = 33.3333 m/s

Reaction time of an alert driver = 0.8 sec

Reaction time of an alert driver = 3 sec

extra time taken by sleepy driver over an alert driver = 3 - 0.8 = 2.2 sec

now, extra distance that car will travel in case of sleepy driver  will be'

S_d = V × 2.2 sec

S_d = 33.3333 m/s × 2.2 sec

S_d = 73.3333 m

hence, number of car of additional car length  n will be;

n = S_n / car length

n = 73.3333 m / 5m

n = 14.666 ≈ 15

Therefore, the number of additional car lengths approximately it takes the sleepy driver to stop compared to the alert driver is 15

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3 years ago
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When is the magnitude of the acceleration of a mass on a spring at its maximum value?
Andreas93 [3]

Answer:

A. when the mass has a speed of zero

Explanation:

In mass-spring system, the velocity and the acceleration are in anti-phase, which means that when one of the two quantities is maximum, the other one is zero, and vice-versa.

In fact:

- When the displacement of the spring is zero (x=0), the velocity is maximum, due to conservation of energy. In fact, as the displacement is zero, the elastic potential energy of the system (given by \frac{1}{2}kx^2) is zero, therefore the kinetic energy (given by \frac{1}{2}mv^2) must be maximum, and so the velocity (v) is also maximum. On the cotnrary, acceleration (a) is directly proportional to the restoring force of the spring, given by

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- When the displacement of the spring is maximum, the velocity is zero, due to conservation of energy. In fact, as the displacement is maximum, the elastic potential energy of the system (given by \frac{1}{2}kx^2) is maximum, therefore the kinetic energy (given by \frac{1}{2}mv^2) must be zero, and so the velocity (v) is also zero. On the cotnrary, since acceleration (a) is directly proportional to the restoring force of the spring, given by

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so we see that when x=maximum, then the force is maximum, and so the acceleration is maximum as well.

Based on this, the correct answer is

A. when the mass has a speed of zero


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Answer:

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