Answer:
im pretty sure it is C. Insulation
Explanation:
because it says reduced, and basically ur insulating the fire.
F = ma
So if you want the "a" to stay constant (as it is then uniform acceleration), the F must also be constant to apply a constant force.
2 is the answer
Answer: Normal Force of the ground pushing the athlete up.
Explanation: I did this on Khan Academy and got the answer right.
<span>Answer:
initial I = (m/2)L²/3 + (m/2)L²
where L = ½ the length of the rod, and the vertical half can be treated as a point mass.
initial I = mL²(1/6 + 1/2) = 2mL²/3
final I = m(2L)²/3 = 4mL²/3
Since I has doubled and momentum is conserved, ω has halved.
ω = 3.9 rad/s.
Formulaically: 2mL²/3 * 7.8rad/s = 4mL²/3 * ω</span>
