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natima [27]
4 years ago
9

Which statement is equivalent to newtons first law

Physics
2 answers:
Shkiper50 [21]4 years ago
5 0

Answer:

Explanation:

The concept of linear momentum is equivalent to Newton's first law.

As per linear momentum, it is defined as the product of mass and velocity of any object.

When this law of conservation of linear momentum is applied on a single particle, this becomes equivalent to Newton's first law.

larisa [96]4 years ago
3 0

Newtons first law states "an object at rest will stay at rest while an object in motion will remain in motion" im confused as to what you are asking for but heres an example.

a car traveling at a speed of 35mph coming up to a stop sign has to slow down to a stop it cant stop instantly thats the same for it accelerating.

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Answer:

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A satellite of mass M = 270kg is in circular orbit around the Earth at an altitude equal to the earth's mean radius (6370 km). A
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To solve this problem we will apply the concepts related to Orbital Speed as a function of the universal gravitational constant, the mass of the planet and the orbital distance of the satellite. From finding the velocity it will be possible to calculate the period of the body and finally the gravitational force acting on the satellite.

PART A)

V_{orbital} = \sqrt{\frac{GM_E}{R}}

Here,

M = Mass of Earth

R = Distance from center to the satellite

Replacing with our values we have,

V_{orbital} = \sqrt{\frac{(6.67*10^{-11})(5.972*10^{24})}{(6370*10^3)+(6370*10^3)}}

V_{orbital} = 5591.62m/s

V_{orbital} = 5.591*10^3m/s

PART B) The period of satellite is given as,

T = 2\pi \sqrt{\frac{r^3}{Gm_E}}

T = \frac{2\pi r}{V_{orbital}}

T = \frac{2\pi (2*6370*10^3)}{5.591*10^3}

T = 238.61min

PART C) The gravitational force on the satellite is given by,

F = ma

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F = \frac{270*9.8}{4}

F = 661.5N

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