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TiliK225 [7]
3 years ago
7

Investigations allow for the control of variables

Physics
2 answers:
Sloan [31]3 years ago
8 0
I believe that the statement is true. <span>Investigations allow for the control of variables. Changing variables will lead you to observations that may prove your hypothesis. Hope this answers the question. Have a nice day. Please feel free to ask more questions.</span>
Bogdan [553]3 years ago
7 0
<h3>I believe that the statement is true. Investigations allow for the control of variables. Changing variables will lead you to observations that may prove your hypothesis</h3>
You might be interested in
How do I find the cosine of theta.
NNADVOKAT [17]

The value of cos θ in the given figure is 0.98.

<h3>What is cosine of an angle?</h3>

The cosine of an angle is defined as the sine of the complementary angle.

The complementary angle equals the given angle subtracted from a right angle, 90.

cos θ = sin(90 - θ)

For example, if the angle is 30°, then its complement is 60°

cos 30 = sin(90 - 30)

cos 30 = sin 60

0.866 = 0.866

<h3>Cosine of an angle with respect to sides of a right triangle</h3>

cos θ = adjacent side / hypotenuse side

adjacent side of the given right triangle is calculated as follows;

adj² = 10² - 2²

adj² = 100 - 4

adj² = 96

adj = √96

adj = 9.8

cos θ = 9.8/10

cos θ = 0.98

Thus, the value of cos θ in the given figure is 0.98.

Learn more about cosine of angles here: brainly.com/question/23720007

#SPJ1

5 0
1 year ago
If the intensity of a loud car horn is 0.005 W/m^2 when you are 2 meters away from the source. Calculate the sound intensity lev
nekit [7.7K]

Answer:

(c) 97 dB sound intensity level

Explanation:

We have given the intensity of the loud car horn I=0.005w/m^2

We know that I_O=10^{-12}w/m^2

Now the sound intensity level is given by \beta =10log\frac{I}{I_0}=10log\frac{0.005}{10^{-12}}=96.98dB , which is nearly equal to 97

So the sound intensity level will be 97 dB

So option (c) will be the correct option

4 0
3 years ago
Which of the following is an example of velocity ?
Mademuasel [1]
The correct answer is c because B) is a vector which includes both velocity and direction
7 0
3 years ago
Read 2 more answers
Which light packs the highest energy per photon? 1. infrared 2. red 3. blue 4. ultraviolet 5. green?
WINSTONCH [101]
A single photon carries an energy equal to
E=hf
where h is the Planck's constant and f is the frequency of the photon.
This means that the higher the frequency of the light, the higher the energy. Among the 5 different options mentioned by the problem, the light with highest frequency is ultraviolet, which has frequencies in the range [3-30] PHz, while visible light (red, blue, green) and infrared have lower frequency, so ultraviolet light has the highest energy per photon.
3 0
3 years ago
a 0.199 kg snowball moving west makes an inelastic collision with a 2.89 kg box moving 0.523 m/s west. afterward,they move west
kogti [31]

Answer:

The initial velocity of the snowball was 22.21 m/s

Explanation:

Since the collision is inelastic, only momentum is conserved. And since the snowball and the box move together after the collision, they have the same final velocity.

Let m_1 be the mass of the ball, and v_1 be its initial velocity; let m_2 be the mass of the box, and v_2 be its velocity; let v_f be the final velocity after the collision, then according to the law of conservation of momentum:

m_1v_1+m_2v_2=v_f(m_1+m_2).

From this we solve for v_1, the initial velocity of the snowball:

\boxed{v_1=\frac{v_f(m_1+m_2)-m_2v_2}{m_1}}

now we plug in the numerical values m_1=0.199\:kg, m_2=2.89\:kg, v_2=0.523\:m/s, and v_f=1.92\:m/s to get:

v_1=\frac{1.92*(0.199+2.89)-2.89*0.523}{0.199}

\boxed{v_1=22.21\:m/s}

The initial velocity of the snowball is 22.21 m/s.

<em>P.S: we did not take vectors into account because everything is moving in one direction—towards the west.</em>

4 0
3 years ago
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