Complete question:
A 5-m³ container is filled with 900 kg of granite (density of 2400 kg/m3). The rest of the volume is air, with density equal to 1.15 kg/m³. Find the mass of air and the overall (average) specific volume.
Answer:
The mass of the air is 5.32 kg
The specific volume is 5.52 x 10⁻³ m³/kg
Explanation:
Given;
total volume of the container,
= 5 m³
mass of granite,
= 900 kg
density of granite,
= 2,400 kg/m³
density of air,
= 1.15 kg/m³
The volume of the granite is calculated as;

The volume of air is calculated as;

The mass of the air is calculated as;

The specific volume is calculated as;
