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Ket [755]
3 years ago
13

What is the relationship between temperature, dew point temperature, and air pressure

Physics
1 answer:
olchik [2.2K]3 years ago
6 0
Dew point is the temperature at which the water vapor in the air condenses , then evaporates. The barometric or air pressure is independent from the dew point. 
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C) Explain the following.<br>Keftles, cooking pans and iron boxes have polished surfaces​
Monica [59]

Answer:

Polished surfaces reduce heat loss

5 0
3 years ago
You have a bowling ball with a mass of 4kg. You throw it with an acceleration of 10 m/s/s. With how much force will it hit the p
Eddi Din [679]

Answer:

<h3>The answer is 40 N</h3>

Explanation:

The force acting on an object can be found by using the formula

<h3>force = mass × acceleration</h3>

From the question

mass = 4 kg

acceleration = 10 m/s²

So we have

force = 4 × 10

We have the final answer as

<h3>40 N</h3>

Hope this helps you

6 0
4 years ago
A car slams on its brakes, coming to a complete stop in 4.0 seconds. The car was traveling south at 60.0 mph. Calculate the acce
denis23 [38]
Alright let's start this off with our basic equation!

Accerlation (a) = ?

Initial velocity (V1)= 60 mph = 88 ft/s (because we HAVE to convert mph to ft/s to match time)

Final velocity (V2) = 0 ft/s because the car stops

Time (t) = 4 seconds

a = \frac{Final velocity - Initial Velocity}{time}
a = \frac{0 - 88}{4}
a = \frac{-88}{4}
a = -22 

Therefore, your acceleration is -22 ft/s² !! Hope this helped and was one of the branliest answers :') 


5 0
4 years ago
Which of the following is not an equation of motion:- v=u+at; s=ut+at; v^2-u^2=2as; s=ut+1/2 at^2​
Sladkaya [172]

Answer:

s=ut+at

its not the equation of motion..

<h2>hope it helps </h2><h2>stay safe healthy and happy.....</h2>
8 0
3 years ago
Un camión tiene una capacidad de 10 toneladas cuantas barras de hierro puede soportar si cada una tiene un volumen de 0.0318 m3
mr Goodwill [35]

Answer:

\#barras=40 barras

Explanation:

Hola.

En este caso, dado el volumen y densidad de cada barra, podemos calcular el peso de cada una en toneladas con la correspondiente conversión de 1 ton = 1000 kg:

m_{barra}=0.0318m^3*7860kg/m^3=250kg*\frac{1ton}{1000kg} =0.25ton

De este modo, si el camión resiste 10 toneladas, el número de barras resulta de la división entre la capacidad del camión y el peso por barra:

\# barras=\frac{10ton}{0.25ton/barra}\\ \\\#barras=40 barras

¡Saludos!

5 0
4 years ago
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