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lora16 [44]
3 years ago
11

A small car with mass m and speed 2v and a large car with mass 2m and speed v both travel the same circular section of an unbank

ed road. If the frictional; force required to keep the small car on the road without skidding is F, then the frictional force required to keep the large car on the road without skidding is
(A) 4F
(B) 2F
(C) F
(D) F/2
(E) F/4
Physics
1 answer:
Alenkasestr [34]3 years ago
5 0

Answer:

(D) F/2

Explanation:

Since the circular section is unbanked, the centripedal acceleration acting on each of the cars is

a_s = \frac{v_s^2}{r} = \frac{(2v)^2}{r} = \frac{4v^2}{r}

a_l = \frac{v_l^2}{r} = \frac{v^2}{r}

Therefore the centripetal force on each car

F_s = m_sa_s = \frac{4mv^2}{r}

F_l = m_la_l = \frac{2mv^2}{r}

Since F_s = 2F_l this means the friction force required to keep the large car on the road is only half of the friction force required to keep the small car on road

So (D) F/2 is the correct answer

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8 0
2 years ago
You want to move a 4- kg bookcase to a different place in the living room. If u push with a force of 65 n and the bookcase accel
IrinaK [193]

Answer:

1.65

Explanation:

The equation of the forces along the horizontal direction is:

F-F_f = ma (1)

where

F = 65 N is the force applied with the push

F_f is the frictional force

m = 4 kg is the mass

a=0.12 m/s^2 is the acceleration

The force of friction can be written as F_f = \mu R (2), where

\mu is the coefficient of kinetic friction

R is the normal force exerted by the floor

The equation of forces along the vertical direction is

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since the bookcase is in equilibrium. Substituting (2) and (3) into (1), we find

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7 0
3 years ago
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