Hello!
A stretched spring has 5184 J of elastic potential energy and a spring constant of 16,200 N/m. What is the displacement of the spring ?
Data:



For a spring (or an elastic), the elastic potential energy is calculated by the following expression:

Where k represents the elastic constant of the spring (or elastic) and x the deformation or displacement suffered by the spring.
Solving:









Answer:
The displacement of the spring = 0.8 m
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Explanation:
1) For a positive point charge, the lines radiate outwards
for a negative point charge, the lines converge inwards
2) F = 2.3 X 10^-26 N
k = 9 X 10^9 N.m²/C
q1 = q2 = e = 1.6 X 10^-19 C
r = ?
F = kq1q2/r²
r² = kq1q2/F
r = √[kq1q2/F ]
r = √0.0100
r = 0.10m
The two protons are 0.10 m apart
3) The unit if electric field intensity is Newton-per-coulomb N/C
Answer:

Explanation:
Ohm's law states the relationship between voltage, resistance and current in an electrical circuit containing passive elements only:

where
V is the voltage supplied by the battery
R is the resistance of the circuit
I is the current
From the equation, we see that the voltage, V, is directly proportional to the current in the circuit, I.