The empirical formula will be CHCl
<h3>What is the empirical formula?</h3>
The simplest whole number ratio of atoms in a compound is the empirical formula of a chemical compound in chemistry. Sulfur monoxide's empirical formula, SO, and disulfur dioxide's empirical formula, S2O2, are two straightforward examples of this idea. As a result, both the sulfur and oxygen compounds sulfur monoxide and disulfur dioxide have the same empirical formula. They do not, however, have the same molecular formula, which specifies how many atoms are present in each molecule of a chemical compound.
For saran
C= 24.8% ,
H= 2.0% ,
Cl = 73.1%
= 24.8/ 12 = 2.0
= 2.0/1=2.0
= 73.1/ 35 = 2.0
Now, dividing each mole by the smallest moles (hydrogen's moles), one obtains:
C= 2.0 / 2.0 = 1
H= 2.0/2.0 = 1
Cl = 2.0/ 2.0 = 1
The empirical formula will be CHCl
Learn more about empirical formula here:-
brainly.com/question/14044066
#SPJ4
I think it's false I'm just guessing
Molar mass sucrose ( C12H22O11 ) = 342 g/mol
8.0 g of O2 <span>is the limiting factor of the reaction reagent
</span>
C12H22O11 + 12 O2 ------------> 12 CO2 + 11 H2O
1 mol C12H22O11 ------------- 342 g
x mol C12H22O11 ------------- 10 g
x = 10 / 342
x = 0,029 mol of sucrose
answer A
1. Answer;
=56 g/mol
Explanation and solution;
PV = nRT
nRT= mass/molar mass (RT)
molar mass = (mass/V ) × (RT/P)
= Density × (RT/P)
Molar mass = 2.0 g/L × (0.0821 × 323 K)/0.948 atm
Molar mass = 56 g/mol
2. Answer;
Molecular mass is C4H8
Explanation;
Empirical mass × n = molar mass
Empirical mass for CH2 = 14 g/mol
Therefore;
56 g/mol = 14 g/mol × n
n = 4
The molecular formula= 4(CH2)
= C4H8
No, they don't. The wavelength increases from violet to red. No, they don't. The wavelength increases from violet to red.
Hope this helps