SO2 is not likely to be ionic.
An ionic bond is most commonly formed between a metal and a non-metal.
K (potassium) and Br (bromine) are a metal and non-metal pair.
Al (aluminum) and Cl (chlorine) are a metal and non-metal pair.
S (sulfur) and O (oxygen) are both non-metals, and likely formed a covalent bond instead of an ionic bond, which is common for two non-metals.
Given parameters:
Mass of rectangular block of copper metal = 2695g
Dimensions of the block = 4.8cm x 5.5cm x 6.4cm
Unknown;
Density of the copper = ?
To solve this problem, we apply the density formula.
Density is an intensive property of all matter. It is defined as the mass per unit volume of any substance.
Mathematically,
Density =
The unit is usually in kg/m³ or g/cm³
Now, we need to derive the volume since mass is given already.
Volume of the rectangular block = length x width x height
= 4.8cm x 5.5cm x 6.4cm
= 168.96cm³
Let's solve for the density now;
input the parameters and solve;
Density of rectangular copper block =
= 15.95g/cm³
The density of the copper rectangular block is 15.95g/cm³
True!
Explanation:
Dialysis is the separation of smaller molecules from larger molecules or of dissolved substances from colloidal particles in a solution by selective diffusion through a semipermeable membrane. The most common usage is that of blood, or kidney dialysis, but the process can be used for sea or drinking water as well.
Answer:
Hey how are you all doing the answer is 8.93 g
Explanation:
Answer:
The specific heat of the unknown substance is 1.22 J/g.°C.
Explanation:
Heat lost by substance (Qc) = Heat gained by the water (Qw)
,
<em>- (Qc) = (Qw).</em>
<em></em>
- We can calculate the amount of heat (Qw) gained by water using the relation:
Qw = m.c.ΔT,
where, Qw is the amount of heat released to water (Q = ??? J).
m is the mass of water (m = 110.0 g).
c is the specific heat capacity of solution (c = 4.18 J/g.°C).
ΔT is the difference in T (ΔT = final temperature - initial temperature = 32.4°C - 24.2°C = 8.2°C).
<em>∴ Q = m.c.ΔT = </em>(110.0 g)(4.18 J/g.°C)(8.2°C) = <em>3770.36 J.</em>
- Now, the amount of heat lost by the substance <em>(Qc) = - 3770.36 J.</em>
(Qc) = m.c.ΔT,
where, Qc is the amount of heat lost by substance (Qc = - 3770.36 J).
m is the mass of water (m = 42.5 g).
c is the specific heat capacity of solution (c = ??? J/g.°C).
ΔT is the difference in T (ΔT = final temperature - initial temperature = 32.4°C - 105.0°C = -72.6°C).
∴ (- 3770.36 J) = (42.5 g)(c)(-72.6°C).
∴ c = (- 3770.36 J)/(42.5 g)(-72.6°C) = 1.222 J/g.°C.