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goblinko [34]
3 years ago
14

How are plan and animal cells different?

Chemistry
2 answers:
Dafna1 [17]3 years ago
7 0

Answer: Animal cells are mostly round and irregular in shape while plant cells have fixed rectangular shapes.

Explanation:

Your welcome

Ber [7]3 years ago
6 0
The key difference between plant and animal cells lies in the structural differences. Plant cells are rectangular wheres animal cells are round and plant cells contain chloroplasts, a cell wall, and vacuoles while animal cells do not.
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n the 1990’s, the Boeing Co. developed a process for treating wastewater from electroplating and printed circuit board manufactu
scZoUnD [109]

Answer:

Final concentrations:

Cu²⁺ = 0

Al³⁺ = 3.13 mmol/L = 84.51 mg/L

Cu = 4.7 mmol/L = 300 mg/L

Al = 0.57 mmol/L = 15.49 mg/L

Explanation:

2Al (s) + 3Cu²⁺ (aq) → 2Al³⁺ (aq) + 3Cu (s)

Al: 27 g/mol ∴ 100 mg = 3.7 mmol

Cu: 63.5 g/mol ∴ 300 mg = 4.7 mmol

3 mol Cu²⁺ _______ 2 mol Al

4.7 mmol Cu²⁺ _____ x

x = 3.13 mmol Al

4.7 mmol of Cu²⁺ will be consumed.

3.13 mmol of Al will be consumed.

4.7 mmol of Cu will be produced.

3.13 mmol of Al³⁺ will be produced.

0.57 mmol of Al will remain.

6 0
2 years ago
The molecule CH20 contains two single bonds and one double bond.<br> True<br> False
dem82 [27]

Answer:

True

Explanation:

The molecule CH20 contains two single bonds and one double bond.

6 0
2 years ago
What is the third alkali metal ​
andrey2020 [161]

Answer:

potassium

The third alkali metal is K (potassium). The atomic number of K (potassium) is 19. Thus, the atomic number of third alkali metal is 19

Explanation:

3 0
2 years ago
Read 2 more answers
what would be the ph of an aqueous solution of sulphuric acid which is 5×10^_5 mol l^_1 in concentration​
guajiro [1.7K]

Answer:

the ph of an aqueous solution of sulphuric acid which is 5*10^5 mol in concentration is basic in nature

6 0
2 years ago
How many moles of nitrogen, N, are in 61.0 g of nitrous oxide, N2O?
Oksana_A [137]

Answer:

2.77 mol N

Explanation:

M(N2O) = 2*14 + 16 = 44 g/mol

61.0 g * 1 mol/44g = (61/44) mol N2O

                       N2O ---- 2N

                    1 mol         2 mol

            (61/44) mol        x mol

x = (61/44)*2/1 = 2.77 mol N

4 0
3 years ago
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