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3 years ago

How is a sodium ion symbol written? so so- na na-

Chemistry

2 answers:

vfiekz [6]3 years ago

6 0

A sodium ion symbol is written as Na^+.

koban [17]3 years ago

5 0

Answer: Na⁺ or Na⁺¹

Explanation: Sodium as an element of the first group of the periodic system has atomic number 11. This means that there are 11 electrons negatively charged around the nucleus, and also 11 protons in the nucleus that are positively charged. As is known, the number of electrons and protons should be equal within the element to keep the element neutral. In order for the sodium element to become a sodium ion, one electron leaves its place and has 10 electrons, which is one less than the number of protons in the nucleus, so that the sodium ion is positive. The ion symbol is written by adding the superscript on the right as + or - in addition to the symbol of the element that is first written, depending on which ion is in question. In this case, + should be written as a superscript.

Also if the charge of the ion is say, +2 then it is written as a superscript behind the element symbol as +2. If it is +1 like with sodium ion, then only + can be written.

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What does Gibbs free energy depend on? O A. It depends on the rate and quantity of the reaction. O B. It depends on the activati

Oksana_A [137]

Answer:

C: It depends on the entropy and enthalpy of the reaction.

Explanation:

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3 years ago

Two equilibrium reactions of nitrogen with oxygen, with their corresponding equilibrium constants (Kc) at a certain temperature,

7nadin3 [17]

Answer:

Kc = 1.54e - 31 / 2.61e - 24

Explanation:

1 ) $N_{2}(gas) + O_{2}(gas)\rightarrow 2NO(gas)$ ; Kc = 1.54e - 31

2) $N_{2}(gas) + 1/2O_{2}(gas)\rightarrow N_{2}O(gas)$ ; Kc = 2.16e - 24

upon reversing ( 2 ) equation

$N_{2}O(gas)\rightarrow N_{2}(gas) + 1/2O_{2}(gas)$ Kc = 1/2.16e - 24

now adding 1 and reversed equation (2)

$N_{2}(gas) + O_{2}(gas)\rightarrow 2NO(gas)$

$N_{2}O(gas)\rightarrow N_{2}(gas) + 1/2O_{2}(gas)$

we get ,

$N_{2}O(gas) + 1/2O_{2}(gas)\rightarrow 2NO(gas)$ Kc = 1.54e-31 × 1/2.61e - 24

equilibrium constant of equation (3) is -

Kc = 1.54e - 31 / 2.61e - 24

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natta225 [31]

Answer:

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Neptune planet has the coldest surface temperature

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