The tire pressure is the sum of gauge pressure and the standard pressure of atmospheric pressure
We know that the standard air pressure of surrounding = 101.325 kPa
The given gauge pressure = 413 kPascal
So the tire pressure = 101.325 kPa + 413 = 514.325 K Pa
We can also convert the given pascals to atmosphere or Torr or mmHg or bar
I am pretty sure it was composed of mostly CO₂.
Is soluble in water but not soluble in acetonitrile.
So i think its false
Assuming that none of the liquid evaporates, the mass of the ice would be the same as the mass of the water because no chemical change occurred, only a phase change occurred.
Hope this helps