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MariettaO [177]
4 years ago
8

How do you identify the zero reference position for calculating mechanical potential energy? What is the most common zero refere

nce position for system that has gravitational potential energy?
Physics
1 answer:
ANTONII [103]4 years ago
8 0
<span>The zero reference position should be the position the system has the least potential energy. As an object falls, its potential energy is converted into kinetic energy. Gravity's ability to do work (potential energy) reaches zero when it hits the ground and stops falling, hence the ground is the most common zero reference position.</span>
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Use an example to describe the difference between tangential and centripetal acceleration
Tpy6a [65]

Answer:

Say you are holding a thread to the end of which is tied a stone. Now when you start whirling it around you will notice that two forces have to be applied simultaneously. One which pulls the thread inwards and the other which throws it sideways or tangentially.

Both these forces will generate their respective accelerations.

The one pointed inwards will generate centripetal or radial acceleration.

The one pointing sideways will generate tangential acceleratio

Explanation:

A major difference between tangential acceleration and centripetal acceleration is their direction

Centripetal means “center seeking”. Centripetal acceleration is always directed inward.

Tangential acceleration is always directed tangent to the circle.

Tangential acceleration results from the change in magnitude of the tangential velocity of an

object. An object can move in a circle and not have any tangential acceleration. No tangential

acceleration simply means the angular acceleration of the object is zero and the object is moving

with a constant angular velocity

6 0
4 years ago
A 495-kg dragster accelerates from rest to a final speed of 105 m/s in 395 m, during which it encounters an average frictional f
drek231 [11]

Answer:

Explanation:

According to energy conservation which states that the workdone is equal to change in the system

Workdone = change in kinetic energy + (frictional force * distance)

Workdone = ΔK + fd

Workdone = kf-Ki + fd

Workdone = = 1/2(m(v-u)^2) + fd

Given

Mass m = 495kg

final velocity v = 105m/s

initial velocity = 0m/s

Force f= 1400N

distance d = 395m

Substitute

Workdone = 1/2(495(105-0)^2) + 1400(395)

Workdone = 2,728,687.5+553000

Workdone = 3,281,687.5 Joules

Time = 8.2secs

Power output = Workdone/Time

Power output = 3,281,687.5/8.2

Power output = 885,766.768

Power output = 8.858 * 10^5 watts

3 0
4 years ago
A concave mirror is used to ______ ( converge, diverge) light and a convex mirror is used to _____( diverge or converge )
Colt1911 [192]

Answer:

converge, diverge

Explanation:

4 0
3 years ago
Read 2 more answers
1. When two atoms of the same nonmetal react, they often form a(an)
kkurt [141]

When two atoms of the same nonmetal react,they form what we know today as a diatomic molecule.

Please mark brainliest. :)

7 0
3 years ago
A particle with kinetic energy equal to 282 J has a momentum of magnitude 26.4 kg · m/s. Calculate the speed (in m/s) and the ma
masha68 [24]

Answer:

v=21.36\,\,\frac{m}{s}\\

m=1.2357\,\,kg

Explanation:

Recall the formula for linear momentum (p):

p = m\,v  which in our case equals 26.4 kg m/s

and notice that the kinetic energy can be written in terms of the linear momentum (p) as shown below:

K=\frac{1}{2} m\,v^2=\frac{1}{2} \frac{m^2\,v^2}{m} =\frac{1}{2}\frac{(m\,v)^2}{m} =\frac{p^2}{2\,m}

Then, we can solve for the mass (m) given the information we have on the kinetic energy and momentum of the particle:

K=\frac{p^2}{2\,m}\\282=\frac{26.4^2}{2\,m}\\m=\frac{26.4^2}{2\,(282)}\,kg\\m=1.2357\,\,kg

Now by knowing the particle's mass, we use the momentum formula to find its speed:

p=m\,v\\26.4=1.2357\,v\\v=\frac{26.4}{1.2357} \,\frac{m}{s} \\v=21.36\,\,\frac{m}{s}

4 0
3 years ago
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