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givi [52]
3 years ago
5

Please help me with this question​

Physics
1 answer:
Ksju [112]3 years ago
4 0

Answer:

i can not read that sorry

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A point at which parts of an artificial structure are joined. Hope this helps
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Why is the moon's umbra much smaller during a solar eclipse?
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7 0
2 years ago
You wind a small paper tube uniformly with 153 turns of thin wire to form a solenoid. The tube\'s diameter is 5.11 mm and its le
lina2011 [118]

The concept required to solve this problem is linked to inductance. This can be defined as the product between the permeability in free space by the number of turns squared by the area over the length. Recall that Inductance is defined as the opposition of a conductive element to changes in the current flowing through it. Mathematically it can be described as

L = \frac{\mu N^2 A}{l}

Here,

\mu = Permeability at free space

N = Number of loops

A = Cross-sectional Area

l = Length

Replacing with our values we have,

L = \frac{(4\pi *10^{-7})(153)^2(\pi (\frac{5.11*10^{-3}}{2})^2)}{2.47*10^{-2}}

L = 0.00002442H

L = 24.42\mu H

Therefore the Inductance is 24.42\mu H

3 0
3 years ago
6th grade science !!!!!!!!!!!!!!!​
posledela

Answer:

71

Explanation:

5 0
3 years ago
You go rock climbing with a pack that weighs 70 N and you reach a height of 30 m. how much work did you do to lift your pack? If
Vikentia [17]
When you climb, earth exerts gravitational force on pack in downward direction(pointing towards the center of earth).
In order to climb, you need to work against work done by gravity on the pack.
Hence work done by you = work done by gravity on pack 
                                        = Force x displacement = 70 x 30 = 2100 J.
 
So you need to do 2100 joules of work to lift your pack.

Power is the rate of work done.
Therefore power = work done by you/time(in seconds)
                            =     2100/600 =3.5 watts 
8 0
3 years ago
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