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3 years ago

The two waves shown below pass through the same medium in the phases shown and interfere with each other.

Physics

2 answers:

ale4655 [162]3 years ago

5 0

A. W

Explanation:

The wave that would be produced by the interaction of the two waves shown in the diagram is wave W.

There is no wave in the diagram W.

This type of interference is known as destructive interference.

Destructive interference occurs when two waves out of phase comes together.
In this way, they cancel out each other and are terminated.
If the two waves are in phase, they will reinforce one another.
When waves reinforce one another, a constructive interference has occurred.

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Color in soap bubbles brainly.com/question/8733443

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Phoenix [80]3 years ago

5 0

Answer:

The correct answer is X

Explanation:

When waves pass through the same point they can interfere with each other. When this happens, their amplitudes add together.

Since the two original waves were in phase with each other, their amplitudes add constructively, as shown in diagram X.

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The height of a helicopter above the ground is given by h = 3.15t3, where h is in meters and t is in seconds. At t = 2.10 s, the

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Answer:

The mailbag will take 2.44 seconds to reach the ground.

Explanation:

The height of a helicopter above the ground is given by:

$h = 3.15\times t^3$

Height of helicopter at t = 2.10 seconds

$h(2.10 )=3.15\times (2.10 )^3 m=29.17 m$

The helicopter releases a small mailbag from the height of 29.17 m.

The initial velocity of mailbag = u = 0 m/s

Duration in which mailbag will reach the ground = T

Acceleration due to gravity = g = $9.8 m/s^2$

Using second equation of motion ;

$s=ut+\frac{1}{2}gt^2$

We have , s = 29.17

u = 0 m/s

t = T

$29.17m=0 m/s\times T+\frac{9.8 m/s^2\times T^2}{2}$

Solving for T, we gte :

T = 2.44 seconds

The mailbag will take 2.44 seconds to reach the ground.

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3 years ago

An object is place 30.5 cm from a convex lens that has a focal length of 8.0cm.where is the image ?

77julia77 [94]

Answer:

Image is between F and 2F. And the exact location is:

q = 10.84 cm

Explanation:

The convex lens form different kinds of images with different sizes and locations, for the different positions of an object. In this case, the object is placed 30.5 cm from the convex lens with a focal length of 8 cm. This means that it is the case of the object placed beyond 2F. In this case, the image formed has the following characteristics:

1. Image is real.

2. Image is inverted

3. Image is diminished

4. Image is located between F and 2F

For exact location we use the thin lens formula:

$\frac{1}{f} = \frac{1}{p} + \frac{1}{q}$

where,

f = focal length = 8 cm

p = object distance = 30.5 cm

q = image distance = ?

Therefore,

$\frac{1}{8\ cm} = \frac{1}{30.5\ cm} + \frac{1}{q} \\\frac{1}{8\ cm} - \frac{1}{30.5\ cm} = \frac{1}{q}$

q = 10.84 cm

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