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aalyn [17]
3 years ago
9

The two waves shown below pass through the same medium in the phases shown and interfere with each other.

Physics
2 answers:
ale4655 [162]3 years ago
5 0

A. W

Explanation:

The wave that would be produced by the interaction of the two waves shown in the diagram is wave W.

There is no wave in the diagram W.

This type of interference is known as destructive interference.

  • Destructive interference occurs when two waves out of phase comes together.
  • In this way, they cancel out each other and are terminated.
  • If the two waves are in phase, they will reinforce one another.
  • When waves reinforce one another, a constructive interference has occurred.

learn more:

Color in soap bubbles brainly.com/question/8733443

#learnwithBrainly

Phoenix [80]3 years ago
5 0

Answer:

The correct answer is X

Explanation:

When waves pass through the same point they can interfere with each other. When this happens, their amplitudes add together.

Since the two original waves were in phase with each other, their amplitudes add constructively, as shown in diagram X.

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PLEASE HELP ME I DONT UNDERSTAND THIS AND THIS IS TIMED
mixer [17]

(C)

Explanation:

The circle has a radius r = 0.5 m, which means that its circumference C is

C = 2\pi r = 2\pi(0.5\:\text{m}) = 3.14\:\text{m}

One revolution means that the stopper travels a distance equal to the circumference of the circle so the velocity of the stopper is

v = \dfrac{C}{t} =\dfrac{3.14\:\text{m}}{0.2\:\text{s}} = 15.7\:\text{m/s} \approx 16\:\text{m/s}

5 0
2 years ago
Mass is a measure of weight. True False
8_murik_8 [283]

Answer: False

Explanation: Mass is a measure of the amount of matter in an object.

5 0
3 years ago
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A "biconvex" lens is one in which both surfaces of the lens bulge outwards. Suppose you had a biconvex lens with radii of curvat
Stolb23 [73]

Answer: f=150cm in water and f=60cm in air.

Explanation: Focal length is a measurement of how strong light is converged or diverged by a system. To find the variable, it can be used the formula:

\frac{1}{f} = (nglass - ni)(\frac{1}{R1} - \frac{1}{R2}).

nglass is the index of refraction of the glass;

ni is the index of refraction of the medium you want, water in this case;

R1 is the curvature through which light enters the lens;

R2 is the curvature of the surface which it exits the lens;

Substituting and calculating for water (nwater = 1.3):

\frac{1}{f} = (1.5 - 1.3)(\frac{1}{10} - \frac{1}{15})

\frac{1}{f} = 0.2(\frac{1}{30})

f = \frac{30}{0.2} = 150

For air (nair = 1):

\frac{1}{f} = (1.5 - 1)(\frac{1}{10} - \frac{1}{15})

f = \frac{30}{0.5} = 60

In water, the focal length of the lens is f = 150cm.

In air, f = 60cm.

5 0
3 years ago
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Underground water is being pumped into a pool whose cross section is 3 m x 4 m while water is discharged through a 0.076m-diamet
Svetllana [295]
Given:

Area of pool = 3m×4m
Diameter of orifice = 0.076m
Outlet Velocity = 6.3m/s
Accumulation velocity = 1.5cm/min

Required:

Inlet flowrate

Solution:

The problem can be solved by this general formula.

Accumulation = Inlet flowrate - Outlet flowrate
Accumulation velocity × Area of pool = Inlet flowrate - Outlet velocity × Area of orifice

First, we need to convert the units of the accumulation velocity into m/s to be consistent.

Accumulation velocity = 1.5cm/min × (1min/60s)×(1m/100cm)
Accumulation velocity = 0.00025 m/s

We then calculate the area of the pool and the area of the orifice by:

Area of pool = 3 × 4 m²
Area of pool = 12m²

Area of orifice = πd²/4 = π(0.076m)²/4
Area of orifice = 0.00454m²

Since we have all we need, we plug in the values to the general equation earlier

Accumulation velocity × Area of pool = Inlet flowrate - Outlet velocity × Area of orifice

0.00025 m/s × 12m² = Inlet flowrate - 6.3m/s × 0.00454m²

Transposing terms,

Inlet flowrate = 0.316 m³/s
6 0
3 years ago
1. The basic building block of matter are atoms. Every atom is basically a tiny sphere. Every atom is composed of 2 regions, the
Bogdan [553]

The answers would be:

1. Electron cloud

2. Electrons, Electrons, Electrons

3. Nucleus, nucleus

4. Protons, protons

5. Neutrons, Neutrons

6. Direct, direct.

7. Inverse, inverse

8. No relationship, no relationship

9. Experimental control

10. Controlled variables

Here is more about the question:

An atom has 3 subatomic particles:

Proton: positively charged particles

Electron: Negatively charged particles

Neutrons: Neutrally charged particles

The nucleus is made up of the protons and neutrons, while the electrons are found outside, within the electron cloud.

Electrons are very important in bonding. It is also heavily involved in electricity. Electricity is the flow of electrons through a conductor.

Relationships in a graph:

For direct relationships, you just need to remember, when one goes up, the other one goes up too.

Inverse relationships on the other hand, when one goes up the other goes down.

If no change occurs, then we can say that there is no relationship.

6 0
3 years ago
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