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3 years ago

How long would it take to have $1335.60 in interest if principal is $5300 and interest rate is 7%

1 answer:

5 0

(5300 + 1335.6) = 5300(1 + 0.07)^n where n is the number of years required

6635.6 = 5300(1.07)^n
(1.07)^n = 1.252
n log 1.07 = log 1.252

n = log 1.252 / log 1.07 = 3.32 years Answer

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A skyscraper has 49 floors there are 26 offices on each of the bottom 31 fours the top 18 floors each have 38 officers about how

Anettt [7]

Answer:

903 offices

Step-by-step explanation:

Total number of officers in the sky scraper

= 26 + 31 + [(49-2)×18]

= 26 + 31 + 846

= 903 offices

3 0

2 years ago

Which sums are equal to 1hold 6/8?

katovenus [111]

A. = 7/8
b. = 7/4 = 1 3/4
c. = 7/4 = 1 3/4
d. = 7/4 = 1 3/4

= b,c,d

6 0

3 years ago

Reasoning triangle $abc$ has a perimeter of $12$ units. the vertices of the triangle are $a(x,\ 2),\ b(2,-2)$ , and $c(-1,\ 2)$

OlgaM077 [116]

hmmm let's find the distance between B and C first off.

$~~~~~~~~~~~~\textit{distance between 2 points} \\\\ B(\stackrel{x_1}{2}~,~\stackrel{y_1}{-2})\qquad C(\stackrel{x_2}{-1}~,~\stackrel{y_2}{2})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ BC=\sqrt{(~~-1 - 2~~)^2 + (~~2 - (-2)~~)^2} \implies BC=\sqrt{(-1 -2)^2 + (2 +2)^2} \\\\\\ BC=\sqrt{( -3 )^2 + ( 4 )^2} \implies BC=\sqrt{ 9 + 16 } \implies BC=\sqrt{ 25 }\implies BC=5$

hmmm if BC is that much, then AB + AC = 7, since AB + AC + BC = 12 which is the perimeter, Check the picture below.

6 0

1 year ago

A statistics professor plans classes so carefully that the lengths of her classes are uniformly distributed between 48.0 and 58.

Yanka [14]

Answer: 0.025

Step-by-step explanation:

Given : A statistics professor plans classes so carefully that the lengths of her classes are uniformly distributed between the interval [48.0 minutes, 58.0 minutes].

The probability density function :-

$f(x)=\dfrac{1}{58-48}=\dfrac{1}{10}$

Now, the probability that a given class period runs between 50.25 and 50.5 minutes is given by :-

$\int^{50.5}_{50.25}\ f(x)\ dx\\\\=\int^{50.5}_{50.25}\ \dfrac{1}{10}\ dx\\\\=\dfrac{1}{10}|x|^{50.5}_{50.25}\\\\=\dfrac{1}{10}\ [50.5-50.25]=\dfrac{1}{10}\times(0.25)=0.025$

Hence, the probability that a given class period runs between 50.25 and 50.5 minutes =0.025

Similarly , the probability of selecting a class that runs between 50.25 and 50.5 minutes = 0.025

5 0

3 years ago

Solve the absolute value equation graph the solution 2 |3x-5| -8=8

Mila [183]

2 | 3x - 5 | - 8 = 8

=> 2 | 3x - 5 | = 8 + 8

=> 2 | 3x - 5 | = 16

=> | 3x - 5 | = 16 / 2

=> | 3x - 5 | = 8

=> 3x - 5 = 8        or     3x - 5 = - 8

=> 3x = 13           or     3x = - 3

=> x = 13 / 3              or        x = - 1

=> x = 4 and 1/3        or x = - 1

So, the answer is the second option x = - 1 or x = 4 1/3

The graph of such solutions are just the point in the real line.

For x = 4 1/3, divide the segment from 4 to 5 in three equal parts (add two divisions between 4 and 5) and mark your point in the first division after 4.

4 0

3 years ago