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leonid [27]
3 years ago
9

Find the area of a circle that measures 8 cm from the center to the edge. Use 3.14 for π.

Mathematics
2 answers:
Zepler [3.9K]3 years ago
7 0

Answer:

Area of the circle =25.12 cm ^2

Step-by-step explanation:

So, we have 8 cm as a diameter.

So, Radius will be half of it i.e 4 cm.

Now, Area of circle = pir^2

= 3.14 * 4* 2

= 25.12 cm ^2

Hope it helps!

kobusy [5.1K]3 years ago
5 0
The answer is 25.12 cm^2
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Ierofanga [76]

The area of the triangle is 2\sqrt{3} = 3.4641 square feet.

Step-by-step explanation:

Step 1:

According to the Pythagorean theorem, the square of the hypotenuse will be equal to the sum of the squares of the other two sides.

In the given triangle, the hypotenuse is the side that is represented by c. The other sides on the triangle are represented by the values a and b.

Step 2:

Assume the other side of the triangle measures x units.

So according to the Pythagorean theorem,

4^{2} = (2\sqrt{3} )^{2} + x^{2} , x^{2} = 4^{2} - (2\sqrt{3} )^{2} .

x^{2}  = 16 - 12 =4, x =2.

So the other side of the triangle, b measures 2 feet.

Step 3:

The area of a triangle is half the product of its base length and height.

The base length of this triangle is 2\sqrt{3} feet and the height is 2 feet.

The area of the triangle= \frac{1}{2} (2\sqrt{3} )(2) = 2\sqrt{3} = 3.4641.

The area of the triangle is 2\sqrt{3} = 3.4641 square feet.

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