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3 years ago

What is the gram formula mass of caso4.2h2o?

2 answers:

8 0

So your practically trying to finding the molar mass of CaSO₄.2H₂O and that is found by adding all the molar masses of the individual elements:

So Ca = 40 g/mol
S = 32 g/mol
O = 16 /mol
H = 1 g/mol

molar mass of CaSO₄.2H₂O = [(40) + (32) + (16 × 4) + (2 × 1 × 2) + (2 × 16)]
= 172 g/mol

rodikova [14]3 years ago

7 0

Answer : The gram formula mass of $CaSO_4.2H_2O$ is, 172 g/mole

Explanation :

As we know that,

Molar mass of calcium (Ca) = 40 g/mole

Molar mass of sulfur (S) = 32 g/mole

Molar mass of oxygen (O) = 16 g/mole

Molar mass of hydrogen (H) = 1 g/mole

Now we have to calculate the gram formula mass of $CaSO_4.2H_2O$

In $CaSO_4.2H_2O$ , there are 1 calcium atom, 1 sulfur atom, 6 oxygen atom and 4 hydrogen atom.

The gram formula mass of $CaSO_4.2H_2O$ = $40+32+6(16)+4(1)=172g/mole$

Therefore, the gram formula mass of $CaSO_4.2H_2O$ is, 172 g/mole

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Can someone please check my answer??!!!

Ksenya-84 [330]

Answer:

I think its correct

5 0

3 years ago

Read 2 more answers

A piece of copper absorbs 5000 J of energy and undergoes a temperature change from 100 °C to 200 °C. What is the mass of the pie

irakobra [83]

Answer:

B.) 129.9 grams

Explanation:

To find the mass, you need to use the following equation:

Q = mcΔT

In this equation,

-----> Q = energy (J)

-----> m = mass (g)

-----> c = specific heat (J/g°C)

-----> ΔT = change in temperature (°C)

The specific heat of copper is 0.385 J/g°C. Knowing this, you can plug the given values into the equation and simplify to isolate "m".

Q = mcΔT <----- Equation

5000 J = m(0.385 J/g°C)(200 °C - 100 °C) <----- Insert values

5000 J = m(0.385 J/g°C)(100) <----- Subtract

5000 J = m(38.5) <----- Multiply 0.385 and 100

129.9 = m <----- Divide both sides by 38.5

8 0

1 year ago

How many moles of carbon dioxide are produced when 23.0 g of C3H2O3 is burned during the

Mars2501 [29]

Moles of Carbon dioxide : 0.75

<h3>Further explanation</h3>

Given

23 g C₃H₈O₃

Required

Moles of Carbon dioxide

Solution

Reaction

2C₃H₈O₃ + 7O₂ → 6CO₂ + 8H₂O

mol C₃H₈O₃ :

= mass : MW

= 23 g : 92,09382 g/mol

= 0.24975

From the equation, mol ratio of C₃H₈O₃ : 3CO₂ = 1 : 3, so mol CO₂ :

= 3/1 x mol C₃H₈O₃

= 3/1 x 0.24975

= 0.74925≈0.750 mol

5 0

3 years ago

A voltaic cell made of a Cr electrode in a solution of 1.0 M in Cr3+ and a gold electrode in a solution that is 1.0 M in Au3+.

Vikki [24]

Answer: a) Anode: $Cr\rightarrow Cr^{3+}+3e^-$

Cathode: $Au{3+}+3e^-\rightarrow Au$

b) Anode : Cr

Cathode : Au

c) $Au^{3+}+Cr\rightarrow Au+Cr^{3+}$

d) $E_{cell}=2.14V$

Explanation: -

a) The element Cr with negative reduction potential will lose electrons undergo oxidation and thus act as anode.The element Au with positive reduction potential will gain electrons undergo reduction and thus acts as cathode.

At cathode: $Au{3+}+3e^-\rightarrow Au$

At anode: $Cr\rightarrow Cr^{3+}+3e^-$

b) At cathode which is a positive terminal, reduction occurs which is gain of electrons.

At anode which is a negative terminal, oxidation occurs which is loss of electrons.

Gold acts as cathode ad Chromium acts as anode.

c) Overall balanced equation:

At cathode: $Au{3+}+3e^-\rightarrow Au$ (1)

At anode: $Cr\rightarrow Cr^{3+}+3e^-$ (2)

Adding (1) and (2)

$Au^{3+}+Cr\rightarrow Au+Cr^{3+}$

d) $E^0_(Cr^{3+}/Cr)$ = -0.74 V