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timurjin [86]
3 years ago
9

How many moles of carbon dioxide are produced when 23.0 g of C3H2O3 is burned during the

Chemistry
1 answer:
Mars2501 [29]3 years ago
5 0

Moles of Carbon dioxide : 0.75

<h3>Further explanation</h3>

Given

23 g C₃H₈O₃

Required

Moles of Carbon dioxide

Solution

Reaction

2C₃H₈O₃ + 7O₂ → 6CO₂ + 8H₂O

mol C₃H₈O₃ :

= mass : MW

= 23 g : 92,09382 g/mol

= 0.24975

From the equation, mol ratio of C₃H₈O₃ : 3CO₂ = 1 : 3, so mol CO₂ :

= 3/1 x mol C₃H₈O₃

= 3/1 x 0.24975

= 0.74925≈0.750 mol

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Consider the reactivity of phenol, bromobenzene, toluene, and nitrobenzene toward electrophilic aromatic substitution.
AlexFokin [52]

Answer:

The most reactive compound is:<u> Phenol </u>  because the<u> electron donating</u> character of the <u>alcohol group</u> increases the rate of the reaction.

The least reactive compound is <u>nitrobenzene</u>

because the <u>electron withdrawing</u> character of the<u> nitro group</u> decreases the rate of the reaction.

Explanation:

  • PHENOL-: Any of a group of organic compounds with a hydroxyl (OH) group bound to a carbon atom in an aromatic ring is known as phenol. The word phenol is also the basic name for its simplest member, monohydroxybenzene (C6H5OH), also known as benzenol or carbolic acid, in addition to being the common name for the entire family.
  • ELECTRON DONATING CHARACTER-: Via the carbon atom it is bound to, an electron donating group (EDG) has the net effect of increasing electron density in a molecule. EDGs alter a molecule's reactivity by increasing electron density on neighboring carbon atoms: EDGs make nucleophiles stronger.
  • ALCOHOL GROUP-:Each of a class of organic compounds that have one or more hydroxyl (OH) groups bound to an alkyl group's carbon atom (hydrocarbon chain)is called Alcohol. Alcohols are organic compounds of water (H_2O) in which one of the hydrogen atoms has been substituted by an alkyl group, which in organic structures is usually expressed by R.
  • NITROBENZENE-:The organic compound nitrobenzene has the chemical formula (C_6H_5NO_2). It's a pale yellow oil that's insoluble in water and smells like almonds. Greenish-yellow crystals form when it freezes. It is made on a wide scale as a precursor to aniline from benzene. It is sometimes used as a solvent in the laboratory, especially for electrophilic reagents.
  • ELECTRON WITHDRAWING GROUP-: An electron withdrawing group (EWG) is a type of group that reduces electron density in a molecule by bonding to a carbon atom. EWGs alter a molecule's reactivity by reducing electron density on neighboring carbon atoms.
  • NITRO GROUP-: The nitro group is one of the most widely used explosophores (functional groups that combine to form a compound explosive). In addition, the nitro group is a heavy electron-withdrawing group. CH bonds alpha (adjacent) to the nitro group may be acidic due to this property.
7 0
3 years ago
A sample of Ne gas has a pressure of 654 mmHg with an unknown volume. The gas has a pressure of 345 mmHg when the volume is 495m
Lemur [1.5K]

Answer:

The initial volume of Ne gas is 261mL

Explanation:

This question can be answered using Ideal Gas Equation;

However, the following are the given parameters

Initial Pressure = 654mmHg

Finial Pressure = 345mmHg

Final Volume = 495mL

Required

Initial Volume?

The question says that Temperature is constant;

This implies that, we'll make use of Boyle's law ideal gas equation which states;

P_1V_1 = P_2V_2

Where P_1 represent the initial pressure

P_2 represent the final pressure

T_1 represent the initial temperature

T_2 represent the final temperature

P_1 = 654mmHg\\P_2 = 345mmHg\\V_2 = 495mL

Substitute these values in the formula above;

654 * V_1 = 345 * 495

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Divide both sides by 654

\frac{654V_1}{654} = \frac{170775}{654}

V_1 = \frac{170775}{654}

V_1 = 261.123853211

V_1 = 261mL (Approximated)

<em>The initial volume of Ne gas is 261mL</em>

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A.
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