How many moles of carbon dioxide are produced when 23.0 g of C3H2O3 is burned during the
1 answer:
Moles of Carbon dioxide : 0.75
<h3>Further explanation</h3>
Given
23 g C₃H₈O₃
Required
Moles of Carbon dioxide
Solution
Reaction
2C₃H₈O₃ + 7O₂ → 6CO₂ + 8H₂O
mol C₃H₈O₃ :
= mass : MW
= 23 g : 92,09382 g/mol
= 0.24975
From the equation, mol ratio of C₃H₈O₃ : 3CO₂ = 1 : 3, so mol CO₂ :
= 3/1 x mol C₃H₈O₃
= 3/1 x 0.24975
= 0.74925≈0.750 mol
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