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leva [86]
4 years ago
9

What is a base used in toothpaste?

Chemistry
2 answers:
stich3 [128]4 years ago
5 0
Sodium fluoride is used in a lot of toothpastes<span />
Svetlanka [38]4 years ago
3 0
Most of toothpastes<span> includes sodium fluoride,silica,sodium lauryl phosphate,sorbitol,water etc. It may neutralise the acid formation in mouth cavity as well as at teeth gaps.So tooth paste is basic in nature.</span>
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Two students pull a box with force of 100 N to the left and 200 N to the right.
laiz [17]

Answer:

net force is 100 N and direction is right

Explanation:

7 0
3 years ago
A chemist needs to neutralize 25.5 L of 3.86 M chloric acid (HClO3). What mass of sodium hydroxide is
Karolina [17]

Answer:

3.94 × 10³ g

Explanation:

Step 1: Write the neutralization reaction

HClO₃ + NaOH = NaClO₃ + H₂O

Step 2: Calculate the moles of chloric acid that react

25.5 L of 3.86 M chloric acid is to be neutralized. The reacting moles are:

25.5L \times \frac{3.86mol}{L} =98.4mol

Step 3: Calculate the required moles of sodium hydroxide

The molar ratio of HClO₃ to NaOH is 1:1. Then, the reacting moles of NaOH are 98.4 moles.

Step 4: Calculate the mass of sodium hydroxide corresponding to 98.4 moles

The molar mass of NaOH is 40.00 g/mol.

98.4mol \times \frac{40.00g}{mol} =3.94 \times 10^{3} g

6 0
3 years ago
What is the IUPAC name of this compund?​
mr_godi [17]

Answer:

3-ethyl-4-methyl Heptane

Explanation:

longest chain is straight .

we start assigning number from where we are close to the branch to this mean its from left hand side. and we saw two chain 1 is ethyl and other is methyl . In alphabetical order e comes first as compare to m so we write ethyl first after that methyl and than in last we write longest chain name with ane (bcz we only have single vonds).

4 0
3 years ago
Read 2 more answers
the gas left in a ussd aerosol can is at a pressure of 103kPa at 25.0 °C. if the can heats up to 50.0°C what is the pressure of
Tanya [424]
75<span>.0°C all you had to do was add them up 

</span>
5 0
3 years ago
What is the electric force on a proton 2.5 fmfm from the surface of the nucleus? Hint: Treat the spherical nucleus as a point ch
sammy [17]

Explanation:

It is known that charge on xenon nucleus is q_{1} equal to +54e. And, charge on the proton is q_{2} equal to +e. So, radius of the nucleus is as follows.

            r = \frac{6.0}{2}

              = 3.0 fm

Let us assume that nucleus is a point charge. Hence, the distance between proton and nucleus will be as follows.

              d = r + 2.5

                 = (3.0 + 2.5) fm

                 = 5.5 fm

                 = 5.5 \times 10^{-15} m     (as 1 fm = 10^{-15})

Therefore, electrostatic repulsive force on proton is calculated as follows.

              F = \frac{1}{4 \pi \epsilon_{o}} \frac{q_{1}q_{2}}{d^{2}}

Putting the given values into the above formula as follows.

           F = \frac{1}{4 \pi \epsilon_{o}} \frac{q_{1}q_{2}}{d^{2}}

              = (9 \times 10^{9}) \frac{54e \times e}{(5.5 \times 10^{-15})^{2}}

              = (9 \times 10^{9}) \frac{54 \times (1.6 \times 10^{-19})^{2}}{(5.5 \times 10^{-15})^{2}}

              = 411.2 N

or,           = 4.1 \times 10^{2} N

Thus, we ca conclude that 4.1 \times 10^{2} N is the electric force on a proton 2.5 fm from the surface of the nucleus.

8 0
4 years ago
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