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3 years ago

Given the following electronic configurations, identify how many valence electrons each atom has.

Chemistry

2 answers:

ololo11 [35]3 years ago

4 0

Answer : Valence electrons in atom A = 1, B = 6 and C = 2.

Explanation :

Valence electrons means the outermost electrons are the ones which involved in bonding. Electrons are arranged in energy levels or shells.

Valence electrons are found in the highest energy orbitals of an element.

The electronic configuration of (Na) is $1s^22s^22p^63s^1$ . The highest energy orbital is 3s orbital which contains 1 electron. So,

The number of valence electrons in (Na) = A = 1

Similarly,

The electronic configuration of (O) is $1s^22s^22p^4$ . The highest energy orbital are 2s and 2p orbitals which contains (2 + 4) = 6 electrons. So,

The number of valence electrons in (O) = B = 6

The electronic configuration of (Fe) is $1s^22s^22p^63s^23p^64s^23d^6$ . The highest energy orbital is 4s orbital which contains 2 electrons. So,

The number of valence electrons in (Fe) = C = 2

Papessa [141]3 years ago

3 0

correct answer would be 1,6, and 8 so a=1, 6, c=8.

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Explanation:

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Answer:

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Explanation:

¡Hola!

En este caso, dado en química se conocen las estructuras de Lewis como representaciones gráficas de como los elementos están enlazados entre sí, debemos tener en cuenta que estos enlaces se forman entre los electrones de valenciam, los cuales son utilizados para su representación. Se sabe que los electrones de valencia son representados con puntos alrededor del elemento a través de puntos que se unen entre sí y son el número de electrons en la capa más externa de los elementos en cuestión; por ejemplo, cloro tiene 7 electrones de valencia, azufre tiene 6, hidrogeno 1, carbono 4 y así sucesivamente.

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Answer:

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