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Maslowich
3 years ago
8

What are kind and number of atoms in ring portion in the haworth structure of glucose

Chemistry
2 answers:
Eddi Din [679]3 years ago
6 0

In the cyclic structure of glucose, there are five carbon atoms and an oxygen atom.

monitta3 years ago
3 0

Answer:

The six member ring and the position of the -OH group on the carbon (#4) identifies glucose from the -OH on C # 4 in a down projection in the Haworth structure). Fructose is recognized by having a five member ring and having six carbons, a hexose.

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A 0.271g sample of an unknown vapor occupies 294ml at 140C and 874mmHg. The emperical formula of the compound is CH2. How many m
Phoenix [80]
Using PV = nRT, we can calculate the moles of the sample.
874 mmHg = 116,524 Pa
n = PV/RT
n = 116,524 x 294 x 10⁻⁶ / 8.314 x (140 + 273)
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moles = mass / Mr
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Mr = 27.2
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Formula of substance:
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3 years ago
an element has an isotope with a mass of 203.973 amu and and abundance of 1.40%. another isotope has a mass of 205.9745 amu with
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Answer is: the average atomic mass 217.606 amu.

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Ar₃ = 206.9745 amu.

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ω₁ = 1.40% = 0.014; mass percentage of isotope.

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ω₄ = 57.40% = 0.574.

Ar = Ar₁ · ω₁+ Ar₂ · ω₂ + Ar₃ · ω₃ + Ar₄ · ω₄.  

Ar = 203.973 amu · 0.014 + 205.9745 amu · 0.241 + 206.9745 amu · 0.221 + 207.9766 amu · 0.574.

Ar = 2.855 amu + 49.632 amu + 45.741 amu + 119.378 amu.

Ar = 217.606 amu.

But abundance of isotopes is greater than 100%.

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Answer:

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erastovalidia [21]

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Because molarity is mol/L, we'll have to convert 17g to mol.

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