In the cyclic structure of glucose, there are five carbon atoms and an oxygen atom.
Answer:
The six member ring and the position of the -OH group on the carbon (#4) identifies glucose from the -OH on C # 4 in a down projection in the Haworth structure). Fructose is recognized by having a five member ring and having six carbons, a hexose.
Make the question more clear for me
Explanation:
I think 7.72 mL
11.1/184 × 128/184=7.72
