In the cyclic structure of glucose, there are five carbon atoms and an oxygen atom.
Answer:
The six member ring and the position of the -OH group on the carbon (#4) identifies glucose from the -OH on C # 4 in a down projection in the Haworth structure). Fructose is recognized by having a five member ring and having six carbons, a hexose.
mass (m) = ? , volume = 18.0 ml , density = 1.42 g/ml .
I hope I helped you^_^
Explanation:
what are you talking about tho
Atomic no. = 8
Mass no. = 16
Period no. = 2
Group no. = 6
Actually Welcome to the Concept of the Acceleration.
a = V2-V1/t
so the correct answer is, a = ∆v/t
option C.) is correct, a = ∆v/t
