Answer:
EMF of the power source, E = 19.34 volts
Explanation:
It is given that,
Voltage at which computer sensor is operated, V = 11.7 V
Power, P = 26.37 W
Total resistance of the power source, R = 2.23 Ohms
Firstly, calculating the current in the circuit. It is calculated as :
![P=I^2R](https://tex.z-dn.net/?f=P%3DI%5E2R)
![I=\sqrt{\dfrac{P}{R}}](https://tex.z-dn.net/?f=I%3D%5Csqrt%7B%5Cdfrac%7BP%7D%7BR%7D%7D)
![I=\sqrt{\dfrac{26.37}{2.23}}](https://tex.z-dn.net/?f=I%3D%5Csqrt%7B%5Cdfrac%7B26.37%7D%7B2.23%7D%7D)
I = 3.43 A
Let E is the emf of the power source. It is given by,
![E=V+IR](https://tex.z-dn.net/?f=E%3DV%2BIR)
![E=11.7+3.43\times 2.23](https://tex.z-dn.net/?f=E%3D11.7%2B3.43%5Ctimes%202.23)
E = 19.34 volts
Hence, the EMF of the power source is 19.34 volts. Hence, this is the required solution.
Solving for acceleration:
F = ma
10000 = 2000*a
a = 5 m/s^2
Solving for velocity:
Vf = Vi + a(t)
0 = Vi - (5)(6)
Vi = 30 m/s
Solving for displacement or distance:
S = Vi*t - 1/2 * a * t^2
S = 30(6) - 1/2 (5)(6)^2
S = 90m
The car would have traveled 90m before coming to rest.
Answer:
D.
Explanation:
small, hard, abundant, sensitive to temperature change, and easily preserved
Answer:
Option C. Its image falls on the periphery of the retina, denser in rods
Explanation:
This can be explained as the photo receptors present in the outer periphery are more sensitive to light and enable us to see clearly dimly lit objects.
Also the peripheral vision is the the one on the retinal periphery which is highly rich in concentration of rods than cones and thus a dimly lit object at night with peripheral vision gives a clearer image of the object.
The central vision makes use of the central part, i.e., fovea which is dense with the concentration of cones, photo-receptors which enable us to see different colors and functions well in bright light.
Answer:
x = 2.69 cm
Explanation:
We are given ;
Density of oil; ρ_oil = 924 kg/m³
Density of wood; ρ_wood = 970 kg/m³
h = 3.79cm
Density of water ( ρ_water) has a constant value of 1000 kg/m³
At equilibrium position, we have;
ρ_wood•g•h - ρ_oil•g•(h - x) - ρ_water•g•x = 0
This is because the density of oil is lower than that of water while density of wood is higher than that of oil but lower than that of water.
x is the distance below the interface between the two liquids is the bottom of the block.
Thus, let's make x the subject;
x = [(ρ_wood - ρ_oil)/(ρ_water - ρ_oil)] x h
Plugging in the relevant values to get ;
x = [(970 - 924)/(1000 - 924)] x 3.79
x = (54/76) x 3.79 = 2.69cm