Answer:
(a)11.24 m/s
(b)7.44 m/s
(c)409 N
(d)
(e) 0
Explanation:
The period for 1 circle
of the merry go around is 9.5s. It means the angular speed is:

(a)The speed is

(b) Centripetal acceleration:

(c) Magnitude of the force that keeps you go around at this acceleration

(d) let the coefficient of friction by
. The frictional force shall be this coefficient multiplied by normal force reverting gravity of the man

If an experiment is conducted such that an applied force is exerted on an object, a student could use the graph to determine the net work done on the object.
The graph of the net force exerted on the object as a function of the object’s distance traveled is attached below.
- A student could use the graph to determine the net work done on the object by Calculating the area bound by the line of best fit and the horizontal axis from 0m to 5m
For more information on work done, visit
brainly.com/subject/physics
Answer:
v = 19.6 m/s.
Explanation:
Given that,
The radius of the circle, r = 5 m
The time period of the ball, T = 1.6s
We need to find the ball's tangential velocity.
The formula for the tangential velocity is given by :

Putting all the values in the above formula

So, the tangential velocity of the ball is 19.6 m/s. Hence, the correct option is (c).
Solid particles hope this helped!