A disoriented physics professor drives 3.22 km north, then 4.75 km west, then 1.90 km south. find the magnitude and direction of
1 answer:
It can be noted that the directions west and north are perpendicular to each other. hence we can use the right angle formula for calculating total distance in these directions. Also South is just negative north. This technique is called euclidean distance norm. It is the basis of Cartesian coordinate system.
Total distance = 3.22 N + 4.75 W +1.90 S
= 1.32 N + 4.75 W
D =
D = 4.93 Km
direction = atan(N/W) = 15.53 deg north of west
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Since force is a vector quantity, we can find the net force by determining the resultant force. The equation is written below:
F = √(Fx²)+(Fy)²
where
Fx is the force parallel to the ground
Fy is the downward force
F = √(1.2×10⁻⁶ N)²+(1.27×10⁻⁵ N)²
F = 1.2788×10⁻⁵ N
Then, we apply Newton's second law of motion.
F = ma
a = F/m = 1.2788×10⁻⁵ N/(6×10⁻⁷ kg)
a = 21.31 m/s²
<em>The magnitude of the acceleration is 21.31 m/s². The direction is shown in the picture, which is headed towards southeast.</em>
F = √(Fx²)+(Fy)²
where
Fx is the force parallel to the ground
Fy is the downward force
F = √(1.2×10⁻⁶ N)²+(1.27×10⁻⁵ N)²
F = 1.2788×10⁻⁵ N
Then, we apply Newton's second law of motion.
F = ma
a = F/m = 1.2788×10⁻⁵ N/(6×10⁻⁷ kg)
a = 21.31 m/s²
<em>The magnitude of the acceleration is 21.31 m/s². The direction is shown in the picture, which is headed towards southeast.</em>