The velocity with which the jumper leaves the floor is 5.1 m/s.
<h3>
What is the initial velocity of the jumper?</h3>
The initial velocity of the jumper or the velocity with which the jumper leaves the floor is calculated by applying the principle of conservation of energy as shown below.
Kinetic energy of the jumper at the floor = Potential energy of the jumper at the maximum height
¹/₂mv² = mgh
v² = 2gh
v = √2gh
where;
- v is the initial velocity of the jumper on the floor
- h is the maximum height reached by the jumper
- g is acceleration due to gravity
v = √(2 x 9.8 x 1.3)
v = 5.1 m/s
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Answer:
0.015 atm
Explanation:
The pressure of the gas can be calculated using Ideal Gas Law:

<u>Where:</u>
n: is the number of moles of the gas
R: is the gas constant = 0.082 L*atm/(K*mol)
V: is the volume of the container = 1.64 L
T: is the temperature
We need to find the number of moles and the temperature. The number of moles is:

<u>Where:</u>
M: is the molar mass of the N₂ = 14.007 g/mol*2 = 28.014 g/mol
m: is the mass of the gas = 0.226 g

Now, the temperature can be found using the following equation:
<u>Where:</u>
R: is the gas constant = 0.082 L*atm/K*mol = 8.314 J/K*mol
: is the root-mean-square speed of the gas = 182 m/s
By solving the above equation for T, we have:
Finally, we can find the pressure of the gas:

Therefore, the pressure of the gas is 0.015 atm.
I hope it helps you!
Answer:
The acceleration of the wagon is 3 m/s².
To calculate the acceleration of the wagon, we use the formula below.
Formula:
F = ma............. Equation 1
Where:
F = horizontal Force
m = mass of the wagon
a = acceleration of the wagon.
make a the subject of the equation
a = F/m.............. Equation 2
From the question,
Given:
F = 30 N
m = 10 kg
Substitute these values into equation 2
a = 30/10
a = 3 m/s²
Hence, the acceleration of the wagon is 3 m/s².
Using the formula: ΔY = V₀y * t + (1/2) * ay * t²
Solve for time and get: 1.968s
Then use: v = d/t in the x-direction and get: d = 3.936