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sleet_krkn [62]
4 years ago
14

Which particle is most likely to interact with your hand? Select one: a. Alpha particle b. Beta particle c. Gamma particle d. Ne

utrino
Physics
1 answer:
IgorLugansk [536]4 years ago
4 0

Answer:

The correct option is a

Explanation:

The alpha particle has the lowest penetrating power of the trio of alpha, beta and gamma particles and can be stopped by a sheet of paper and hence cannot penetrate a human skin. Beta particle has a higher penetrating power than alpha particle (some of it penetrates the human skin and some do not) while the gamma particle has the highest penetrating power (with all of it penetrating the human skin).

From the above description, it can be deduced that the alpha particle will stay and interact with the hand (because of its low penetrating power) as the remaining particles move through the skin.

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Leviafan [203]

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Answer:

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Explanation:

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5 0
4 years ago
A moving particle is subject to conservative forces only. When its kinetic energy decreases by 10 J, what happens to its mechani
satela [25.4K]

Answer:

Its mechanical energy is the same.

Explanation:

If forces are only conservative, the mechanical energy will be the same.

It can be different if energy get transformed in another kind of energy like elastic energy for example, although the amount of energy is always the same.

If we just have mechanical energy not geting transformed we have:

Em=K+U

Em: Mechanical energy

K: Kinetic energý

U: Potential energy

Then if Kinetic energy decreases 10J, Potential energy will grow up 10J to keep the same amount of mechanical energy.

8 0
3 years ago
Two small plastic spheres are given positive electrical charges. When they are 16.0 cm apart, the repulsive force between them h
katrin2010 [14]

Answer:

a) 7.5425 * 10^-7 C

b) 3.7712 * 10^-7 C ; 1.5085 * 10^-6 C

Explanation:

Part a)

F_{elect} = \frac{k*q_{1}*q_{2} }{R^2} \\q_{1} = q_{2} = q\\q = \sqrt{\frac{F_{elect} * R^2}{k} }\\ = \sqrt{\frac{0.2 * 0.16^2}{9*10^9} }\\\\ q = 7.5425 * 10 ^(-7) C

Part b)

F_{elect} = \frac{k*q_{1}*q_{2} }{R^2} \\q_{1} = 4*q_{2} \\q = \sqrt{\frac{F_{elect} * R^2}{k*4} }\\ = \sqrt{\frac{0.2 * 0.16^2}{4*9*10^9} }\\\\ q_{2}  = 3.7712 * 10 ^(-7) C\\\\q_{1}  = 1.5085 * 10 ^(-6) C

3 0
3 years ago
On a hot day, Dave is relaxing by the pool. He touches the concrete next to the pool and then touches the surface of the water.
Alenkasestr [34]

Answer:

the concrete because the concrete absorbs the suns energy, making it hot

Explanation:

<u><em>Please give me brainliest</em></u>

5 0
3 years ago
Read 2 more answers
Two 120 Ω resistors are connected in parallel across a supply voltage of 10 VDC. What's the current in this circuit?
german

As we know that here two 120 ohm resistors are connected in parallel with the battery of voltage 10 V DC

now here we will use Ohm's law

V = i R

so here we can use above equation to find the current in each resistor

10 = i \times 120

i = \frac{10}{120}

i = 0.0833 A

so here this will be the current flow through each resistor

now the total current through both resistors will be given as

i_{total} = 0.0833 + 0.0833 = 0.167 A


8 0
3 years ago
Read 2 more answers
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