PLZ HELP

How much heat does a 100. g sample of copper absorb when its temperature increases by 30.0°C? The specific heat of copper is 0.3

erica [24]

Answer:

$\boxed {\boxed {\sf B. \ 1170 \ Joules }}$

Explanation:

We are asked to find how much heat a sample of copper absorbs when the temperature is increased.

Since we know the mass, temperature increase, and specific heat capacity, we can use the following formula to calculate heat.

$q= mc \Delta T$

The mass of the copper sample is 100 grams, the temperature is changed or increased by 30.0 degrees Celsius, and the specific heat of copper is 0.39 Joules per gram degrees Celsius.

m= 100 g
c= 0.39 J/g °C
ΔT= 30.0 °C

Substitute the values into the formula.

$q= (100 \ g )(0.39 \ J/g \textdegree C ) (30.0 \textdegree C )$

Multiply the first two values. Note that the units of grams cancel.

$q= 39 \ J/ \textdegree C (30.0 \textdegree C )$

Multiply again, this time the units of degrees Celsius cancel.

$q= 1170 \ J$

The copper sample absorbs 1170 Joules of heat and Choice B is correct.

7 0

3 years ago

The rate constant for the decomposition of nitrogen dioxide NO2(g) LaTeX: \longrightarrow⟶ NO (g) + 1/2 O2(g) with a laser beam

aleksley [76]

Answer :

The time taken by the reaction is 19.2 seconds.

The order of reaction is, second order reaction.

Explanation :

The general formula to determine the unit of rate constant is:

$(Concentration)^{(1-n)}(Time)^{-1}$

Unit of rate constant Order of reaction

$Concentration/Time$ 0

$Time^{-1}$ 1

$(Concentration)^{-1}Time^{-1}$ 2

As the unit of rate constant is $M^{-1}min^{-1}$ . So, the order of reaction is second order.

The expression used for second order kinetics is:

$kt=\frac{1}{[A_t]}-\frac{1}{[A_o]}$

where,

k = rate constant = $1.95M^{-1}s^{-1}$

t = time = ?

$[A_t]$ = final concentration = 0.97 M

$[A_o]$ = initial concentration = 2.48 M

Now put all the given values in the above expression, we get:

$1.95\times t=\frac{1}{0.97}-\frac{1}{2.48}$

$t=0.32min=0.32\times 60s=19.2s$

Therefore, the time taken by the reaction is 19.2 seconds.

8 0

3 years ago

Question 3 of 10

PIT_PIT [208]

Answer:

the moluculer formula is the answer

Explanation:

4 0

3 years ago

At a pressure of 650 kpa 2.2L of hydrogen is used to fill a balloon to a final pressure of 115 kpa. What's the balloons volume?

Alborosie

Answer:

V₂ = 12.43 L

Explanation:

Given data:

Initial pressure = 650 KPa

Initial volume = 2.2 L

Final pressure = 115 KPa

Final volume = ?

Solution:

The given problem will be solved through the Boyles law,

"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"

Mathematical expression:

P₁V₁ = P₂V₂

P₁ = Initial pressure

V₁ = initial volume

P₂ = final pressure

V₂ = final volume

Now we will put the values in formula,

P₁V₁ = P₂V₂

650 KPa ×2.2 L = 115 KPa × V₂

V₂ = 1430 KPa. L/ 115 KPa

V₂ = 12.43 L

4 0

3 years ago

The blank solution used to calibrate the spectrophotometer is 10.0 mL of 0.2 M Fe(NO3)3 diluted to 25.0 mL with 0.1 M HNO3. Why

Sliva [168]

FeNCS+ product...............thats how you do it i believe

4 0

3 years ago