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iogann1982 [59]
3 years ago
15

A forest ecosystem starts with both Sonoran toads and Wood frogs. What would you expect to happen if the ecosystem becomes more

arid (dry) over time?
*important information*

-Sonoran toads have dry skin and don't need much water.

-Wood frogs need to swim to keep their skin wet.​
Chemistry
1 answer:
Gnom [1K]3 years ago
5 0

Answer:

i think that sonoran toads would prosper and wood frogs would disappear

Explanation:

because of the provided information

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A 1.85 kg textbook is sitting on a bookshelf 2.23 m above the floor. How much potential energy does it have?
neonofarm [45]

Answer:

\boxed {\boxed {\sf 40.4299 \ Joules}}

Explanation:

Potential energy is energy due to position. It is the product of mass, height, and acceleration due to gravity.

PE= m \times g \times h

The mass of the textbook is 1.85 kilograms. Assuming this is on Earth, the acceleration due to gravity is 9.8 meters per square second. The height is 2.23 meters.

  • m= 1.85 kg
  • g= 9.8 m/s²
  • h= 2.23 m

Substitute the values into the formula.

PE = 1.85 \ kg \times 9.8 \ m/s^2 \times 2.23 \ m

Multiply the first 2 numbers together.

PE=18.13 \ kg*m/s^2 *2.23 \ m

Multiply again.

PE= 40.4299 \ kg*m^2/s^2

  • 1 kilogram square meter per square second (1 kg*m²/s²) is equal to 1 Joules (J)
  • Our answer of 40.4299 kg*m²/s² is equal to 40.4299 J

PE= 40.4299 \ J

The textbook has <u>40.4299 Joules of potential energy.</u>

7 0
3 years ago
Boyle's Law for gases is:
larisa86 [58]

Answer:

b. just a model and therefore accurate for no real gases

Explanation:

Boyle´s Law was determined and is applied for ideal gases, this is, those gases that:

- Do not have any interaction between their particles (neither attraction nor repulsion)

- Any collision between its particles is perfectly elastic

With these conditions, Boyle found that pressure and volume (in a constant temperature) are inversely proportional, which can be expressed as:

PV = k, where “k” is a constant

So, when pressure increases, volume decreases, and viceversa.  

If we have to different conditions (1 and 2) of pressure and volume (at constant temperature), this can be expressed like:

P₁V₁ = P₂V₂ = constant

The current and complete equation that links temperature, pressure, mass (in moles) and volume is:

PV = nRT

Real gases do not strictly comply with this law, as its particles has interactions and collisions are not perfectly elastic. This law is more accurate for gases with low molecular mass, and with low pressure and/or high temperature conditions (under these conditions, interactions can be neglected)

Another term that can gives us an idea whether a gas is ideal or not, is the compressibility coefficient Z:

Z = PV/RT

For ideal gases, Z = 1 , as long as the gas moves away from ideality, Z is totally different from 1

3 0
3 years ago
If a chemist analyzes a 3.84g sample containing sand and table sugar, and recovers 1.43g of      sand, what  percent by mass of
n200080 [17]
We are given with a mixture of sand and table sugar. The mixture has a mas s of 3.84 grams. After recovery, it was found out that there is 1.43 grams of sand. The amount of table sugar then is 3.84-1.43 or 2.41 grams. This is equal to 2.41/3.84 or 62.76% by mass/
4 0
3 years ago
The structure that houses dna
Alecsey [184]

The nucleus (plural, nuclei) houses the cell's genetic material, or DNA, and is also the site of synthesis for ribosomes, the cellular machines that assemble proteins. Inside the nucleus, chromatin (DNA wrapped around proteins, described further below) is stored in a gel-like substance called nucleoplasm.

4 0
3 years ago
For a school event 1/6 of the athletic field is reversed for the fifth -grade classes the reserved part of the field is divided
SVETLANKA909090 [29]

Answer:

\frac{1}{24}

Explanation:

Given:

For a school event, 1/6 of the athletic field is reserved for the fifth -grade classes and the reserved part of the field is divided equally among the 4 fifth grade classes in the school.

To find: fraction of the whole athletic field reserved for each fifth class

Solution:

Fraction of the whole athletic field reserved for four fifth classes = \frac{1}{6}

So, fraction of the whole athletic field reserved for each fifth class = \frac{1}{4}(\frac{1}{6})=\frac{1}{24}

3 0
3 years ago
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