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velikii [3]
3 years ago
8

Burning one gallon of gasoline releases 20 pounds of CO2 into the air. Harry’s compact car can travel 25 miles on one gallon of

gas. If Harry drives 15,000 miles in a year, his vehicle will add pounds of CO2 to the atmosphere.
Chemistry
1 answer:
son4ous [18]3 years ago
5 0
There are several information's already given in the question. Based on those information's, the answer can be easily deduced.
Amount of gasoline required by Harry's car to travel 25 miles = 1 gallon
Then
amount of gasoline required
by Harry's car to travel 15000 miles = 15000/25
                                                         = 600 gallons
So 
Amount of CO2 released by burning 1 gallon of gasoline = 20 pounds
Then
Amount of CO2 released
by burning 600 gallon of gasoline = 600 * 20
                                                      = 12000 pounds
From the above deduction, it can be concluded that the amount of CO2 that will be added by Harry's car to the atmosphere is 12000 pounds.
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What is a huge organic molecule composed of many smaller molecules called?
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Answer:

Macromolecules. A very large organic molecule composed of many smaller molecules, 1)Carbohydrates, 2)proteins, 3)lipids, 4)nucleic acids. Three of the four classes of macromolecules that are polymers. 1.Carbohydrates.

7 0
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What makes a balloon electrically charged?
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C. Rubbing the balloon against your hair
3 0
2 years ago
Read 2 more answers
How many moles are in 12 liters of Cl2?
RoseWind [281]

Answer:

\boxed {\boxed {\sf 0.54 \ mol \ Cl_2}}

Explanation:

A mole is any quantity of a substance that contains 6.02 × 10²³ particles. At standard temperature and pressure, or STP, 1 mole of as is equal to 22.4 liters. This is true for any gas, regardless of the specific kind.

Although it is not specified, we can assume this gas is at STP. Let's set up a ratio using this information: 22.4 L/mol

\frac {22.4 \ L \ Cl_2}{1 \ mol \ Cl_2}

Multiply by the given number of liters: 12

12 \ L \ Cl_2 *\frac {22.4 \ L \ Cl_2}{1 \ mol \ Cl_2}

Flip the ratio so the liters of chlorine cancel.

12 \ L \ Cl_2 * \frac {1 \ mol \ Cl_2}{22.4 \ L \ Cl_2}

12  * \frac {1 \ mol \ Cl_2}{22.4 }

\frac {12}{22.4 }  \ mol \ Cl_2

0.53571428571 \ mol \ Cl_2

The original measurement of liters has 2 significant figures, so our answer must have the same.

For the number we found, that is the hundredth place.

  • 0.53<u>5</u>71428571

The 5 in the thousandth place tells us to round the 3 up to a 4.

0.54 \ mol \ Cl_2

12 liters of chlorine gas at STP is approximately <u>0.54 moles of chlorine gas.</u>

8 0
3 years ago
Calculate the mass of 4 moles of sodium hydroxide
harina [27]

Answer:

Mass = 160 g

Explanation:

Given data:

Number of moles of sodium hydroxide = 4 mol

Mass of sodium hydroxide = ?

Solution:

Formula:

Mass = number of moles × molar mass of sodium hydroxide

Molar mass of sodium hydroxide = 40 g/mol

Mass = 4 mol × 40 g/mol

Mass = 160 g

4 0
3 years ago
Consider the complete reaction of 43.0 g of silicon with excess nitrogen gas in the reaction shown below. What mass of product f
kupik [55]
The answer to your question is : no.of moles of Si = 43/atomic mass of Si = 43/28.1 = 1.53

according to reaction 3 moles of Si gives 1 mole of Si3N4

so 1.53 mole of Si will give 1.53/3 = 0.51 mole of Si3N4

molar mass of Si3N4 = 140.28 g/mole

it means that 1 mole of Si3N4 = 140.28 g

so 0.51 mole of Si3N4 = 0.51 X 140.28 = 71.543 g
7 0
3 years ago
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