Question

At 650 mm hg a gas has a volume of 190 l what is its volume at standard pressure

Answer 1

Answer:Volume occupied by the gas at standard pressure is 162.5 L.

Explanation:

Pressure of the gas when it occupies volume of 190 L = 650 mmHg

Volume occupied by the gas when the gas is at standard pressure.

The value of standard pressure = 1 atm = 760 mmHg

$P_1=650 mmHg,V_1=190 L,P_2=760 mmHg,V_2=?$

According to Boyle's Law: $Pressure\propto \frac{1}{Volume}$ (at constant temperature)

$P_1\times V_1=P_2\times V_2$

$V_2=\frac{P_1\times V_1}{P_2}=\frac{650 mmHg\times 190 L}{760 mmHg}=162.5 L$

Volume occupied by the gas at standard pressure is 162.5 L.