The head loss in a turbulent flow in a pipe varies Approximant as square of velocity • Direct as the velocity • Invers as square

Question

3 years ago

12

of velocity • Invers as square of dimeter

2 answers:

Tcecarenko [31] · Answer 1 · 2022-03-04T00:36:59+03:00

Answer:

The correct answer is head varies directly with square of velocity of flow

Explanation:

The head loss in a pipe as given by Darcy Weisebach equation is

$h_L=\frac{flv^2}{2gD}$

where

'f' is friction factor whose value depends on the nature of flow (Laminar/turbulent)

'L' is the length of the section in which the head loss is calculated

'v' is the velocity of the flow

'D' is the diameter of the duct

Thus we can see that the head loss varies with square of velocity of the fluid.

Eddi Din [679] · Answer 2 · 2022-03-03T22:40:08+03:00

Answer:

Head loss in turbulent flow is varying as square of velocity.

Explanation:

As we know that head loss in turbulent flow given as

$h_F=\dfrac{FLV^2}{2gD}$

Where

F is the friction factor.

L is the length of pipe

V is the flow velocity

D is the diameter of pipe.

So from above equation we can say that

$h_F\alpha V^2$

It means that head loss in turbulent flow is varying as square of velocity.

We know that loss in flow are of two types

1.Major loss :Due to surface property of pipe

2.Minor loss :Due to change in momentum of fluid.