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3 years ago

What is the acceleration of a full bottle of water dropped fron a desk

Physics

1 answer:

Elodia [21]3 years ago

8 0

The acceleration of the bottle is $g=9.8 m/s^2$ downward

Explanation:

When an object is in free fall (=only the force of gravity is acting on it), its acceleration is equal to the acceleration of gravity.

In fact, the only force acting on the object is the force of gravity, whose magnitude is:

$F=mg$

where

m is the mass of the object

$g=9.8 m/s^2$ is the acceleration of gravity

According to Newton's second law, the net force on the object is equal to the product between its mass (m) and its acceleration (a), so

$F=ma$

By combining the two equations, we get

$mg=ma\\a = g$

Therefore, the acceleration of any object in free fall (and so, also of the bottle in the problem) is $g=9.8 m/s^2$ .

Learn more about weight and forces:

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A pilot heads his jet due east. The jet has a speed of 475 mi/h relative to the air. The wind is blowing due north with a speed

oksian1 [2.3K]

Explanation:

a. The velocity of the wind as a vector in component form will be represented as v vector:

$v=30j$

b.The velocity of the jet relative to the air as a vector in component form will be represented as u vector

$u=475i$

c. The true velocity of the jet as a vector will be represented as w:

$w=u+v$

$w=475i+30j$

d. The true speed of the jet will be calculated as:

$IwI=\sqrt{(475)^2+(30)^2}$

$IwI=\sqrt{225625+900}$

$IwI=\sqrt{226525}$

$IwI=476 mi/h$

e. The direction of the jet will be:

$tita=tan^{-1}\frac{30}{475}$

$tita=tan^{-1}(0.0632)$

$tita=3.62degrees,or,N86.38degreesS$

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2 years ago

When you put a pot of water on the stove, the stove transfers thermal energy to the water. As the water gains large

STALIN [3.7K]

Answer:

It releases some of the energy into the atmosphere as hot steam.

Explanation:

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2 years ago

To determine the height of a tall building such as Sears Tower in Chicago, Illinois a ball was dropped from the top of the build

Darya [45]

Answer:

The height of Sears Tower is 1448.5 feet.

Explanation:

<h3>We apply the free fall formula to the ball: </h3><h3> $y=v_{o} *t+\frac{1}{2} *g*t^{2}$ </h3><h3>y: The vertical distance the ball moves at time t </h3><h3> $v_{o}$ i: Initial speed </h3><h3>g=Gravity acceleration= $9.8*(\frac{\frac{1ft}{0.305m} }{s^{2} } )$ </h3>

Known information

We know that the vertical distance (y) that the ball moves in 9,5s is equal to height of Sears Tower (h).

Too we know that the ball is released from rest, then, $v_{0}$ =0