The energy that was lost due to air resistance while she was bouncing is determined as 3,360 J.
<h3>Conservation of energy</h3>
The amount of energy lost due to air resistance while she was bouncing is determined from the principle of conservation of energy.
ΔE = P.E - Ux
ΔE = mgh - ¹/₂kx²
ΔE = (50)(9.8)(16) - ¹/₂(35)(16)²
ΔE = 3,360 J
Thus, the energy that was lost due to air resistance while she was bouncing is determined as 3,360 J.
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Answer:
when the body is resting N = 246.96 N
when the body is resting on a tilted surface N = 212.12 N.
when the body is in a elevator N = 317.036 N
Explanation:
when the block is resting on a stationary surface the normal force is balanced by the weight of the body.
weight of the body = mg = 25.2×9.8 = 246.96 N
therefore normal force = 246.98 N.
when the block is resting on a tilted surface the normal force will be balanced by the
component of the weight where Ф is the angle of inclination.
therefore N = mg
N= 212.12 N.
when the block is resting on a elevator that is accelerated upward the normal force will be the sum of weight and force due to acceleration ma
therefore N = 246.98 + 25.2×2.78
N = 317.036 N
To solve this problem we will apply the concepts related to resistance as a function of temperature, product of the relationship between the squared voltage and the power. Mathematically this is,

Here,
R = Resistance (At function of temperature)
v = Voltage
P = Power
Then we have,
R at 140°C (7 times room temperature),


The relationship between normal temperature and increased temperature would then be given by,




Therefore the correct value of the group of answer is 1350
Answer:
what if I do and b then someone else c I don't have enough time pls
A cause the sugar cubes are small enough to dissolve fast