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Gemiola [76]
4 years ago
6

Suppose a particle is accelerated through space (no gravity) by a 10 N force. Suddenly the particle encounters a second force of

10 N in the opposite direction of the first force while the first force is still present. The particle
Physics
1 answer:
iren2701 [21]4 years ago
3 0

please dont mind me just looking for points

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[ b) The time of reverberation of an empty hall without and with 500 audiences is 1.5 sec and 1.4 sec respectively. Find the rev
Lilit [14]

The reverberation time with 800 audiences is 0.875 seconds.

<h3>Reverberation time with 800 audience</h3>

R₁V₁ = R₂V₂

where;

  • R₁ is the reverberation time with 400 audience
  • R₂ is the reverberation time with 800 audience
  • V₁ is initial volume
  • V₂ is final volume

R₂ = R₁V₁/V₂

R₂ = (1.4 x 500) / 800

R₂ = 0.875 seconds

Thus, the reverberation time with 800 audiences is 0.875 seconds.

Learn more about reverberation time here: brainly.com/question/9278479

#SPJ1

4 0
2 years ago
Can I answer my own question
Andre45 [30]

Answer:

<em>Well</em><em> </em><em>okay </em><em>do </em><em>it </em><em>what's</em><em> </em><em>your </em><em>question</em><em> </em><em>?</em><em> </em>

4 0
3 years ago
Read 2 more answers
Compare the energy consumption of two commonly used items in the household. Calculate the energy used by a 1.20 kW toaster oven,
9966 [12]

Answer:

The energy consumption by toaster oven is 432 kJ and that of fluorescent light (CFL) bulb is 435 kJ.

Explanation:

Power of toaster oven, P = 1.2 kW

Time, t = 6 minutes = 360 s

The energy used by toaster oven is given by :

E=P\times t\\\\E=1.2\times 10^3\times 360\\\\E=432000\ J\\\\E=432\ kJ

Power of fluorescent light (CFL) bulb, P' = 11 W

Time, t' = 11 h = 39600 s

Energy used by fluorescent light (CFL) bulb is given by :

E'=P'\times t'\\\\E'=11\times 39600\\\\E'=435600\ J\\\\E'=435\ kJ

So, the energy consumption by toaster oven is 432 kJ and that of fluorescent light (CFL) bulb is 435 kJ.

5 0
3 years ago
What is the net force on the box?
omeli [17]

Answer:

The magnitude of the force net is an acting object multiplied by acceleration of the object

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3 years ago
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adell [148]
Airplane with nose up: The plane's speed through the air is the square root of (80 m/s squared) plus (120 m/s squared. The whole picture is a right triangle, and the plane's speed is the hypotenuse. The angle is the angle whose tangent is (80/120). You can get it from a calculator, a book, a slide rule, or online from the site that rhymes with floogle. The man pulling the load is also a right triangle. The horizontal component is (hypotenuse) times (cosine of the angle). The vertical component is (hypotenuse) times (sine of the same angle). Fill in what you know, look up the sin and cos of 25 degrees and write those in too, and then you can solve for what you have to find.
7 0
3 years ago
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