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Salsk061 [2.6K]
3 years ago
6

A photon has an energy of 5.53 × 10–17 j. what is its frequency in s–1 (h = 6.63 × 10–34 j • s)?

Physics
2 answers:
-BARSIC- [3]3 years ago
6 0
Given: Energy E = 5.53 X 10⁻¹⁷ J;     Velocity of light c = 2.998 x 10⁸ m/s

           Planck's constant h = 6.63 x 10⁻³⁴ J.s

Required: Frequency f = ?

Formula: E = hc/λ  and Frequency f = V/λ

               λ = (6.63 x 10⁻³⁴ J.s)(2.998 X 10⁸ m/s)/(5.53 x 10⁻¹⁷ J)

               λ = 3.59 X 10⁻⁹ m

For Frequency f = ?

               f = c/λ

               f = 2.998 x 10⁸ m/s/3.59 x 10⁻⁹m

               f = 8.35 x 10¹⁶ Hz  


alexandr1967 [171]3 years ago
6 0

The frequency of the photon is 8.34 × 10¹⁶ Hz

<h3>Further explanation</h3>

The term of package of electromagnetic wave radiation energy was first introduced by Max Planck. He termed it with photons with the magnitude is :

\large {\boxed {E = h \times f}}

<em>E = Energi of A Photon ( Joule )</em>

<em>h = Planck's Constant ( 6.63 × 10⁻³⁴ Js )</em>

<em>f = Frequency of Eletromagnetic Wave ( Hz )</em>

The photoelectric effect is an effect in which electrons are released from the metal surface when illuminated by electromagnetic waves with large enough of radiation energy.

\large {\boxed {E = \frac{1}{2}mv^2 + \Phi}}

\large {\boxed {E = qV + \Phi}}

<em>E = Energi of A Photon ( Joule )</em>

<em>m = Mass of an Electron ( kg )</em>

<em>v = Electron Release Speed ( m/s )</em>

<em>Ф = Work Function of Metal ( Joule )</em>

<em>q = Charge of an Electron ( Coulomb )</em>

<em>V = Stopping Potential ( Volt )</em>

Let us now tackle the problem !

<u>Given:</u>

E = 5.53 × 10⁻¹⁷ m

h = 6.63 × 10⁻³⁴ Js

<u>Unknown:</u>

f = ?

<u>Solution:</u>

E = h \times f

5.53 \times 10^{-17} = 6.63 \times 10^{-34} \times f

f = 5.53 \times 10^{-17} \div (6.63 \times 10^{-34})

f \approx 8.34 \times 10^{16} ~ Hz

<h3>Learn more</h3>
  • Photoelectric Effect : brainly.com/question/1408276
  • Statements about the Photoelectric Effect : brainly.com/question/9260704
  • Rutherford model and Photoelecric Effect : brainly.com/question/1458544

<h3>Answer details</h3>

Grade: College

Subject: Physics

Chapter: Quantum Physics

Keywords: Quantum , Physics , Photoelectric , Effect , Threshold , Wavelength , Stopping , Potential , Copper , Surface , Ultraviolet , Light

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2) Fundamental units of \Phi are [\frac{mol}{m^3}]

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\rho measured in [\frac{mol}{ft^3}]

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g measured in [\frac{m}{s^2}]

We can re-write the equation as

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The term 2\gamma \Phi must have the same units of \Psi in order to be added to it. Therefore,

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