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Brut [27]
3 years ago
10

A thermometer is randomly selected and tested. Draw a sketch and find the temperature reading corresponding to Upper P 89​, the

89 th percentile. This is the temperature reading separating the bottom 89 % from the top 11 %.

Physics
1 answer:
andrew11 [14]3 years ago
8 0

Answer:

X_{1}=1.23

Explanation:

Given :

μ = 0

σ = 1

For 89th percentile

using invariant norm ( area, μ, σ )

       = inv. norm ( 0.89, 0, 1 )

       = 1.23

or

P ( x > X_{1} ) = 0.89

P\left ( \frac{X-N}{\sigma } >\frac{X_{1}-0}{1}\right )=0.89

P\left ( Z>Z_{1} )=0.89

Now using Normal table, Z = 1.23

Therefore, \frac{X_{1}-0}{1}=1.23

X_{1}=1.23

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Zanzabum

Answer:

0.429 L of water

Explanation:

First to all, you are not putting the value of the energy given to vaporize water, so, to explain better this problem, I will assume a value of energy that I took in a similar exercise before, which is 970 kJ.

Now, assuming that the water density is 1 g/mL, this is the same as saying that 1 g of water = 1 mL of water

If this is true, then, we can assume that 1 kg of water = 1 L of water.

Knowing this, we have to use the expression to get energy which is:

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Solving for m:

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Now "m" is the mass, but in this case, the mass of water is the same as the volume, so it's not neccesary to do a unit conversion.

Before we begin with the calculation, we need to put the enthalpy of vaporization in the correct units, which would be in grams. To do that, we need the molar mass of water:

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I => is the current.

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