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uranmaximum [27]
3 years ago
10

Why can't you trust the law of gravity? (RIDDLE)

Physics
2 answers:
alukav5142 [94]3 years ago
8 0
Because it will always let you down
GarryVolchara [31]3 years ago
5 0
It will always let u down I've heard this many times haha
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Which layer of the Sun appears pinkish-red during a solar eclipse?
notka56 [123]

Answer:

the answet is the 3 layer of the sun

Explanation:

isaw a solar eclipse and leanerd is

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A mosquito flies toward you with a velocity of 2.4 km/h [E]. If a distance of 35.0 m separates you and the mosquito initially, a
tangare [24]

First convert the speed of mosquito to m/s:

So the mosquito is flying at (2,400/3,600) m/s, or ⅔ m/s. 

<span>

Since you are moving at 2m/s, so this makes the closing velocity between you and the mosquito to be 2⅔ m/s. </span>

Therefore the mosquito will hit your sunglasses at:<span>

35 m / (2⅔ m/s) = 13⅛ seconds. 

2.0 m/s * 13⅛ s = 26¼ m from your initial position. 

<span>⅔ m/s * 13⅛ s = 8¾ m from the mosquito's initial position. </span></span>
7 0
3 years ago
Will give brainliest! how does an engineer use physical science?
pentagon [3]

Answer: gravity, circuits

Explanation:

3 0
3 years ago
A stone is tied to a 0.85-meter cord. it is swung in a circle at a constant rate of 6.0 m/s. what is the centripetal acceleratio
Andrei [34K]

Answer:42.4m/s^2

Explanation:

Velocity(v)=6m/s

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Centripetal acceleration=(v x v) ➗ r

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5 0
3 years ago
Superman is flying 54.5 m/s when he sees
Nady [450]

348.34 m/s. When Superman reaches the train, his final velocity will be 348.34 m/s.

To solve this problem, we are going to use the kinematics equations for constant aceleration. The key for this problem are the equations d=v_{0} t+\frac{at^{2} }{2} and v_{f} =v_{0} +at where d is distance, v_{0} is the initial velocity, v_{f} is the final velocity, t is time, and a is aceleration.

Superman's initial velocity is v_{0}=54.5\frac{m}{s}, and he will have to cover a distance d = 850m in a time t = 4.22s. Since we know d, v_{0} and t, we have to find the aceleration a in order to find v_{f}.

From the equation d=v_{0} t+\frac{at^{2} }{2} we have to clear a, getting the equation as follows: a=\frac{2(d-v_{0}t) }{t^{2} }.

Substituting the values:

a=\frac{2(850m-54.5\frac{m}{s}.4.22s) }{(4.22s)^{2}}=69.63\frac{m}{s^{2}}

To find v_{f} we use the equation v_{f} =v_{0} +at.

Substituting the values:

v_{f} =54.5\frac{m}{s} +(69.63\frac{m}{s^{2}}.4.22s)=348.34\frac{m}{s}

5 0
3 years ago
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