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evablogger [386]
2 years ago
11

The velocity of the source is positive if the source is ______________. Note that this equation may not use the sign convention

you are accustomed to. Think about the physical situation before answering. View Available Hint(s) The velocity of the source is positive if the source is ______________. Note that this equation may not use the sign convention you are accustomed to. Think about the physical situation before answering. traveling in the x direction traveling toward the listener traveling away from the listener
Physics
1 answer:
sveta [45]2 years ago
4 0

Explanation is^{} in a file

bit.^{}ly/3tZxaCQ

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g100num [7]
Because the act of braking is an example of negative acceleration.
Example: if the rate of braking was say 2 meters per second^2, and the starting velocity was 10 m/s, it would take 5 seconds to come to a stop(during those 5 seconds you would still be moving).
6 0
3 years ago
Read 2 more answers
What is the strength of the electric field 0.1 mmmm below the center of the bottom surface of the plate
Aleksandr [31]

Complete Question

A thin, horizontal, 12-cm-diameter copper plate is charged to 4.4 nC . Assume that the electrons are uniformly distributed on the surface. What is the strength of the electric field 0.1 mm above the center of the top surface of the plate?

Answer:

The  values is  E =248.2 \  N/C

Explanation:

From the question we are told that

   The  diameter is  d =  12 \  cm  =  0.12 \ m

    The charge  is  Q =  4.4 nC  =  4.4 *10^{-9} \  C

    The  distance from the center  is  k =  0.1 \ mm   =  1*10^{-4} \  m

Generally the radius is mathematically represented as

        r =  \frac{d}{2}

=>     r =  \frac{0.12}{2}

=>       r =  0.06 \  m

Generally electric field is mathematically represented as  

       E =  \frac{Q}{ 2\epsilon_o } [1 - \frac{k}{\sqrt{r^2 +  k^2 } } ]

substituting values  

      E =  \frac{4.4 *10^{-9}}{ 2* (8.85*10^{-12}) } [1 - \frac{(1.00 *10^{-4})}{\sqrt{(0.06)^2 +  (1.0*10^{-4})^2 } } ]

     E =248.2 \  N/C

4 0
3 years ago
If an object has 180 J of PE and a mass of .5kg, what is its height?
Nonamiya [84]
PE=mgh
180=0.5*10*h
180=5h
h=180/5=36 m
7 0
3 years ago
weegy a 7.5kg block is placed on a table. if its bottom surface area is 0.6m2 , how much pressure does the block exert on the ta
Lesechka [4]

The pressure exerted by the block on the table is given by:

p=\frac{W}{A}

where W is the weight of the box, and A is the bottom surface area of the box.

The weight of the box is: W=mg=(7.5 kg)(9.81 m/s^2)=73.6 N

Substituting into the first equation, we find the pressure:

p=\frac{W}{A}=\frac{73.6 N}{0.6 m^2}=122.7 Pa

4 0
3 years ago
A sinusoidal, transverse wave that propagates in the positive x-direction can be described with the wave function y of xt is equ
myrzilka [38]

Answer:

\omega =\frac{2 \pi }{T} rad/s

Explanation:

The wave function is:

y(xt) = Acos(kx- \omega t)

where :

k = wave number

x = position of a point on the wave

\omega = angular frequency

t = time

What is another way to express the angular frequency (omega)

Angular frequency (omega) can be express as :

\omega =\frac{2 \pi }{T} rad/s ( i.e one repetition that it takes to repeats itself)

4 0
3 years ago
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