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never [62]
3 years ago
13

Which f the following are true for gravity

Physics
1 answer:
alisha [4.7K]3 years ago
6 0

Answer:

Explanation:

number A

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_____ replacement involves one element replacing another element in a compound.
Scorpion4ik [409]

Answer:

Single replacement

Explanation:

A single replacement reaction is a reaction in which the less reactive elements are replaced by the more reactive element in a compound. This is so because the more reactive element are higher in the electrochemical series element than the less reactive elements

3 0
2 years ago
What is the energy of a photon with a frequency of 5 x 10^14 Hz?
zloy xaker [14]

Answer:

3.315 x 10^-19 J

Explanation:

Using Eisten's formula, energy is a product of Plank's constant and photon frequency

E=hf

Where f represent frequency, h is Plank's constant and E is energy.

Substituting frequency with 5 x 10^14 Hz and

Planck's constant is 6.63 x 10^-34 J•s.

E=6.63 x 10^{-34} *5 x 10^{14}=3.315x10^{-19} J

8 0
3 years ago
(4)science who ever gets this right will get a brainlest
Citrus2011 [14]
The anwser is true hope this helps
5 0
3 years ago
Read 2 more answers
A radiographer stands six feet from the x-ray source when performing a portable chest exam and receives an exposure of 2 mGy. If
telo118 [61]

Answer:

  I₂ = 8 mG

Explanation:

The intensity of a beam is

          I = P / A

Where P is the emitted power which is 3) 3

           

Let's use index 1 for the initial position of r₁ = 6 ft and 2 for the second position r₂ = 3 ft

          I₁ A₁  = I₂  A₂

           I₂ = I₁ A₁ / A₂

The area of ​​the beam if we assume that it is distributed either in the form of a sphere is

           A₁ = 4π r²

We substitute

            I₂ = I₁ (r₁ / r₂)²

           I₂ = 2 (6/3)²

           I₂ = 2 4

           I₂ = 8 mG

3 0
2 years ago
Read 2 more answers
A 5kg box slides across the floor with an initial velocity of 5m/s. If the coefficient of kinetic friction between the box and t
4vir4ik [10]

The net force on the block perpendicular to the floor is

∑ F[perp] = F[normal] - mg = 0

so that

F[normal] = (5 kg) g = 49 N

Then

F[friction] = 0.1 F[normal] = 4.9 N

so that the net force parallel to the floor is

∑ F[para] = -4.9 N = (5 kg) a

Solve for the acceleration a :

a = (-4.9 N) / (5 kg) = -0.98 m/s²

Starting with an initial velocity of 5 m/s, the box comes to a stop after time t such that

0 = 5 m/s - (0.98 m/s²) t

⇒   t ≈ 5.1 s

5 0
2 years ago
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