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aniked [119]
2 years ago
14

A spider spins a web with silk threads of density 1300 kg/m3 and diameter 3.0 μm . a typical tension in the radial threads of su

ch a web is 7.0 mn. suppose a fly hits this web. part a which will reach the spider first: the very slight sound of the impact or the disturbance traveling along the radial thread of the web?
Physics
1 answer:
Tema [17]2 years ago
5 0

Answer:

Explanation:

The velocity of a wave in a string is equal to:

v = √(T / (m/L))

where T is the tension and m/L is the mass per length.

To find the mass per length, we need to find the cross-sectional area of the thread.

A = πr² = π/4 d²

A = π (3.0×10⁻⁶ m)²

A = 2.83×10⁻¹¹ m²

So the mass per length is:

m/L = ρA

m/L = (1300 kg/m³) (2.83×10⁻¹¹ m²)

m/L = 3.68×10⁻⁸ kg/m

So the wave velocity is:

v = √(T / (m/L))

v = √(7.0×10⁻³ N / (3.68×10⁻⁸ kg/m))

v ≈ 440 m/s

The speed of sound in air at sea level is around 340 m/s.  So the spider will feel the vibration in the thread before it hears the sound.

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There are 2.2 pounds in a kilogram. if a boys mass is 40kg, what is his height in pounds?
sasho [114]
The simplest way to do this is to set up equivalent fractions, like this- 

\frac{1}{2.2} = \frac{40}{x}

Solve for x by using cross multiplication.

40*2.2= 88
1*x=88
x=88

Therefore, the boy weighs 88lbs. 
3 0
2 years ago
Read 2 more answers
What prevents the pressure from increasing as a cloud contracts due to its gravity?
Vesnalui [34]

Thermal energy is converted to radiative energy via molecular collisions and released as photons.

4 0
2 years ago
The momentum difference of a 3 kg mass with initial velocity of 8 m/s and a final velocity of 16 m/s
8090 [49]

Answer:

6

Explanation:

because if 3kg is 8m/s then 16 divided by 2 is 8 means add 3 to 3 and get the final answer

3 0
3 years ago
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1. 1500j of work was done to move a box 20m. What force was applied to the box ?
Fantom [35]

Answer:

1. 75N

2. 67,983 J (=67.98 kJ)

Explanation:

1. Work = Force x Distance

we are given that Work = 1,500J and Distance = 20m

hence,

Work = Force x Distance

1,500 = Force x 20

Force = 1,500 ÷ 20 = 75N

2. Potential Energy, PE = mass x gravity x change in height

we are given that mass = 165 kg and change in height = 42m

assuming that gravity, g = 9.81 m/s²

Potential Energy, PE = mass x gravity x change in height

Potential Energy, PE = 165 x 9.81 x 42 = 67,983 J (=67.98 kJ)

4 0
3 years ago
Spiderman, whose mass is 70.0 kg, is dangling on the free end of a 12.2-m-long rope, the other end of which is fixed to a tree l
Lana71 [14]

Answer:

U = -3978.8 J

Explanation:

The work of the gravitational force U just depends of the heigth and is calculated as:

U = -mgh

Where m is the mass, g is the gravitational acceleration and h the alture.

for calculate the alture we will use the following equation:

h = L-Lcos(θ)

Where L is the large of the rope and θ is the angle.

Replacing data:

h = 12.2-12.2cos(58.4)

h = 5.8 m

Finally U is equal to:

U = -70(9.8)(5.8)

U = -3,978.8 J

5 0
3 years ago
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