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Artist 52 [7]
3 years ago
14

the brightest , hottest, and most massive stars are the brilliant blue stars designated as spectral class O. if a class O star w

ith a mass of 3.26x10^31 kg has a kinetic energy of 1.10x10^42 j, what is its speed?
Physics
1 answer:
4vir4ik [10]3 years ago
6 0

The speed is 0.956 m / s.

<u>Explanation</u>:

The kinetic energy is equal to the product of half of an object's mass, and the square of the velocity.

                   K.E = 1/2 \times m \times v^{2}

where K.E represents the kinetic energy,

           m represents the mass,

            v represents the velocity.

                  K.E = 1/2 \times m \times v^{2}

    1.10 \times 10^42 = 1/2 \times 3.26 \times 10^31 \times v^{2}

                     v^{2} = (1.10 \times 10^42 \times 2) / (3.26 \times 10^31)

                     v = 0.956 m / s.

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3 years ago
How many miles between a point 60 ° north latitude and 30 ° west longitude and a point 60 ° north latitude and 60 ° east longitu
kramer

-- We're pretty sure that this question is based on an assumption of EARTH, so we know that we're dealing with a sphere of roughly 3.950 miles radius.

-- The distance on the sphere between 30° west and 60° east is 90° of longitude.  That's 1/4 of the total circumference of the circle.  

-- BUT ..... Way up here at 60° N latitude, the circle is not as big as the equator.  It's radius/diameter/circumference is only cos(60°) = 0.5 of the Earth's total.

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Read 2 more answers
The positions of four objects as a function of time are shown
KengaRu [80]

There is no movement in line C and the greatest velocity occurs at line D. The answers are:

1. 0.5 m/s

2. 0.25 m/s

3. 14m and -2m

4. -1 m/s

<h3>What is Position - time Graph ?</h3>

Position time graph is the graph of distance or displacement against time. The slope of the graph is velocity.

The given positions of four objects as a function of time are shown

on the graph to the right.

1.) The velocity of object A will be the slope m of the line A.

Slope m = Δx / Δt

m = (4 - 0) / (8 - 0)

m = 4 / 8

m = 0.5 m/s

Velocity at A = 0.5 m/s

2.) The average velocity of object B will be the slope m of the line B.

Slope m = Δx / Δt

m = (6 - 4) / (8 - 0)

m = 2 / 8

m = 0.25 m/s

The average velocity of object B is 0.25s

3.) The object moved a total distance during the first eight seconds will be 4m for A, 2m for B, and 8m for D

Total distance = 4 + 2 + 8 = 14m

It’s net displacement during the same time will be 2. That is,

Displacement = 8 - 6 = -2m

4.) The greatest speed occurred at line D. The velocity of the object moving at the greatest speed will be the slope of the line D

V = -Δx / Δt

V = -8/8

V = -1 m/s

Therefore, there is no movement in line C and the greatest velocity occurs at line D.

Learn more about velocity time graph here :brainly.com/question/769606

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B because the skater is constantly moving in the same speed to go in a circle .
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