Answer:

Explanation:
Given that,
Initially, the spaceship was at rest, u = 0
Final velocity of the spaceship, v = 11 m/s
Distance accelerated by the spaceship, d = 213 m
We need to find the acceleration experienced by the occupants of the spaceship during the launch. It is a concept based on the equation of kinematics. Using the third equation of motion to find acceleration.

So, the acceleration experienced by the occupants of the spaceship is
.
Answer:
<em>Angular displacement=68.25 rad</em>
Explanation:
<u>Circular Motion</u>
If the angular speed varies from ωo to ωf in a time t, then the angular acceleration is given by:

The angular displacement is given by:

The wheel decelerates from ωo=13.5 rad/s to ωf=6 rad/s in t=7 s, thus:



Thus, the angular displacement is:



Angular displacement=68.25 rad
Answer:
Inward
Explanation:
As the centripetal force acts upon an object moving in a circle at constant speed, the force always acts inward as the velocity of the object is directed tangent to the circle. This would mean that the force is always directed perpendicular to the direction that the object is being displaced. hope this helps :)