Answer:
A) 1.67 x 10 ⁻⁶ m/s
B)5.59 x 
%
Explanation:
A)
Given:
d = 5.0 km,
mₐ = 2.5 x 
kg
u₁ = 4.0 x 10⁴ m/s
= 5.98 x 10 ²⁴ kg
Solve using kinetic conserved energy
mₐ x u₁ + x u₂ = uₓ x (mₐ + )
(2.5 x ) (4.0 x 10⁴ )+ (5.98 x 10 ²⁴ )(0) = uₓ x (2.5 x + 5.98 x 10 ²⁴ )
uₓ = ( 2.5 x x 4.0 x 10⁴ ) / (2.5 x + 5.98 x 10 ²⁴ )
uₓ = 1.67 x 10 ⁻⁶ m/s
B) Assuming earth radius as a R = 1.5 x 10 ¹¹ m
t = 365 days x 24 hr / 1 day x 60 minute / 1 hr x 60s / 1 minute = 31536000 s
t = 31536000 s
D = 2 π R = 2 π( 1.5 x 10 ¹¹ )
D = 9.4247 x 10 ¹¹ m
u₂ = D / t = 9.4247 x 10 ¹¹ / 31536000
u₂ = 29885.775 m/s
% = ( 1.67 x 10 ⁻⁶ m/s ) / (29885.775 m/s) x 100
% = 5.59 x %
Answer:
1/3 m/s
Explanation:
Because the graph goes from 3 to 8 on the Y axis we know that each line is 0.5 and on the X axis each line is 1, Then, the slope , or velocity, is 1/3
see? This graph is kinda set up to throw you.
Is there a 1/3 option for this ??
The work required to raise an object to a height is equal to the gravitational potential energy the object gains. <em>(C)</em>
The terminating pin strikes the preliminary, making it detonate. The flash from the groundwork touches off the black powder. Gas changed over from the consuming powder quickly extends in the cartridge. ... The shot's speed and getting away from gases produce a "blast."
Answer:
the answer choices are at the bottom right?
Explanation:
