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Zanzabum
3 years ago
7

The forces acting on a child in a seat are described by a free body diagram what is the net force

Physics
1 answer:
alekssr [168]3 years ago
5 0

maybe gravity because when you sit gravity holds you down

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What percentage of Sun-like stars exists in multiple-star systems?
natka813 [3]

D. About 25%

25% of stars have compainions

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3 years ago
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Mass of Sun
Paladinen [302]

Answer:

Percentage of mass converted to energy = 99.9 %

Explanation:

By far most of the solar system's mass is in the Sun itself: somewhere between 99.8 and 99.9 percent. The rest is split between the planets and their satellites, and the comets and asteroids and the dust and gas surrounding our star. Seen from afar (on the scale of distances between stars) the presence of the solar system would not be obvious. We would simply see a normal-looking star. Perhaps we would pick up the presence of Jupiter, which makes up two thirds or so of the solar system outside of the Sun, by mass.

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3 years ago
What is one limitation of using renewable
olga2289 [7]
The answer to this question to A. The other choices are positive.
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2 years ago
A 1-mCi source of^60 Co is placed in the center of a cylindrical water-filled tank with an inside diameter of 20 cm and depth of
LenKa [72]

To solve this problem we need the concepts of Energy fluency and Intensity from chemical elements.

The energy fluency is given by the equation

\Psi=4RcE\pi

Where

\Psi =The energy fluency

c = Activity of the source

r = distance

E = electric field

In the other hand we have the equation for current in materials, which is given by

I= I_0 e^{-\mu_{h20}X_{h2o}} e^{-\mu_{Fe}X_{Fe}}

Then replacing our values we have that

I = 1*10^{-3} * 3.3*10^{10} * e ^{-0.06*1.1} e^{-0.058*7.861}

I = 1.3*10^7 Bq

We can conclude in this part that 1.3*10^7Bq is the activity coming out of the cylinder.

Now the energy fluency would be,

\Psi = \frac{cE}{4\pir^2}

\Psi = \frac{1.3*10^7*2*1.25}{4\pi*11^2}

\Psi = 2.14*10^4 MeV/cm^2.s

The  uncollided flux density at the outer surface of the tank nearest the source is \Psi = 2.14*10^4 MeV/cm^2.s

6 0
3 years ago
Can someone help me please
makvit [3.9K]

Answer:

Time, I believe. Pretty sure it's time lol

3 0
3 years ago
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