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jarptica [38.1K]
4 years ago
13

I'm in  my lab, writing an essay about the properties of Bose Einstein Condensate. I forgot the formula of producing the condens

ate. Can someone help me?
Physics
1 answer:
Artyom0805 [142]4 years ago
7 0
This is a big looking question for school and for 5 points.It seems to relate to superfluidity in helium III and helium IV and something called the "lambda" point. Though I can't do it justice yet and here, it looks as though i can find tis in "Heat and Thermodynamics", Mark W Zemansky ...If rho is the density of helium II, rhon the density of the normal part, and rhoz the density of the superfluid part rho=rhon+rhoz.At the lambda point, all the atoms are normal and rhon/rho = 1, whereas at absolute zero all the atoms are superfluid and rhon/rho=0.Best I can do with the info and point available ..ps, I think that both Bose and Einstein were nobel prize winners, and the word "Boson" is in honour of the, I believe, Indian physicist Bose. It is a very interesting question, and I can in no way do it justice here.
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Which formulas have been correctly rearranged to solve for radius? Check all that apply. r = GM central/v^2 r =fcm/v^2 r =ac/v^2
jek_recluse [69]

The orbital radius is: r=\frac{GM}{v^2}

Explanation:

The problem is asking to find the radius of the orbit of a satellite around a planet, given the orbital speed of the satellite.

For a satellite in orbit around a planet, the gravitational force provides the required centripetal force to keep it in circular motion, therefore we can write:

\frac{GMm}{r^2}=m\frac{v^2}{r}

where

G is the gravitational constant

M is the mass of the planet

m is the mass of the satellite

r is the radius of the orbit

v is the speed of the satellite

Re-arranging the equation, we find:

\frac{GM}{r}=v^2\\r=\frac{GM}{v^2}

Learn more about circular motion:

brainly.com/question/2562955

brainly.com/question/6372960

#LearnwithBrainly

7 0
3 years ago
Read 2 more answers
Am un test de rezolvat la fizică mă puteți ajuta
OleMash [197]

Answer:

umm

Explanation:

i don't speak Spanish sorry

5 0
3 years ago
Volume of a cylinder with a diameter of 1.55 cm and a height of 1.34 cm
Bogdan [553]

Answer:

2.53 cm³

Explanation:

Volume of cylinder = πr²h; where h is the height and r is the radius and

π = 3.14 approx.

Volume = 3.14 * (1.55/2)² * 1.34 = 2.53 cm³

I divided 1.55 by 2 because we were given the diameter and not radius. Diameter = radius / 2

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3 years ago
When a liquid is heated to a high temperature, it can become a gas. Which term is used to describe this change of state?
IrinaK [193]
Its called evaporation so its B
7 0
4 years ago
Please help: I don't know how to do these problems
antiseptic1488 [7]
d =2.55.68m and t = 11.36s
In my opinion
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