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jarptica [38.1K]
3 years ago
13

I'm in  my lab, writing an essay about the properties of Bose Einstein Condensate. I forgot the formula of producing the condens

ate. Can someone help me?
Physics
1 answer:
Artyom0805 [142]3 years ago
7 0
This is a big looking question for school and for 5 points.It seems to relate to superfluidity in helium III and helium IV and something called the "lambda" point. Though I can't do it justice yet and here, it looks as though i can find tis in "Heat and Thermodynamics", Mark W Zemansky ...If rho is the density of helium II, rhon the density of the normal part, and rhoz the density of the superfluid part rho=rhon+rhoz.At the lambda point, all the atoms are normal and rhon/rho = 1, whereas at absolute zero all the atoms are superfluid and rhon/rho=0.Best I can do with the info and point available ..ps, I think that both Bose and Einstein were nobel prize winners, and the word "Boson" is in honour of the, I believe, Indian physicist Bose. It is a very interesting question, and I can in no way do it justice here.
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How do resistors in parallel affect the total resistance?
4vir4ik [10]

Answer:

They're going to increase the total resistance as R_{T} = \sum\limits_{i=1}^N \left(\frac{1}{R_i} \right)^{-1}

Explanation:

If the resistors are in parallel, the potential difference is the same for each resistor. But the total current is the sum of the currents that pass through each of the resistors. Then

I = I_1 + I_2 + ... + I_N

where

I_i = \frac{V_i}{R_i}

but

V_i = V_j = V for i,j= 1, 2,..., N

so

I = \frac{V}{R_1}+ \frac{V}{R_2} + ... + \frac{V}{R_N} = \left(\frac{1}{R_1} +\frac{1}{R_2} + ... + \frac{1}{R_N}\right)V = \frac{V}{R_T}

where

R_T = \left(\frac{1}{R_1} +\frac{1}{R_2} + ... + \frac{1}{R_N}\right)^{-1} =\sum\limits_{i=1}^N \left(\frac{1}{R_i} \right)^{-1}

4 0
3 years ago
Which type of reaction is shown here? 2KClO3 + heat —> 2KCl + 302 endothermic reaction exothermic reaction
melamori03 [73]
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7 0
3 years ago
26. A baseball traveling 38 m/s is caught by the catcher. The catcher takes 0.1 seconds to stop the ball. What is the accelerati
Furkat [3]

Answer:

The ball has an acceleration of -380 m/s², this means the ball slows down

An acceleration of -380 m/s² is the equivalent of 38.736 g's

Explanation:

Step 1: Data given

Velocity of the baseball at time t=0 = 38 m/s

At time t, the ball stops. This means v = 0

time before stops = 0.1s

Step 2: Calculate the acceleration

v= v0+at

with v= the velocity of the ball at time t = 0. v= 0

with v0 = the velocity of the ball at time t=0. v0 = 38 m/s

with a= the acceleration in m/s²

with t = time in seconds

0 = 38 + a*0.1

a = -380 m/s²

The ball has an acceleration of -380 m/s², this means the ball slows down

An acceleration of -380 m/s² is the equivalent of 38.736 g's

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3 years ago
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damaskus [11]
It’s should be c
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2 years ago
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Citrus2011 [14]

Answer:

B. Radio waves

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Hope this helps!!

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2 years ago
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