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jarptica [38.1K]
4 years ago
13

I'm in  my lab, writing an essay about the properties of Bose Einstein Condensate. I forgot the formula of producing the condens

ate. Can someone help me?
Physics
1 answer:
Artyom0805 [142]4 years ago
7 0
This is a big looking question for school and for 5 points.It seems to relate to superfluidity in helium III and helium IV and something called the "lambda" point. Though I can't do it justice yet and here, it looks as though i can find tis in "Heat and Thermodynamics", Mark W Zemansky ...If rho is the density of helium II, rhon the density of the normal part, and rhoz the density of the superfluid part rho=rhon+rhoz.At the lambda point, all the atoms are normal and rhon/rho = 1, whereas at absolute zero all the atoms are superfluid and rhon/rho=0.Best I can do with the info and point available ..ps, I think that both Bose and Einstein were nobel prize winners, and the word "Boson" is in honour of the, I believe, Indian physicist Bose. It is a very interesting question, and I can in no way do it justice here.
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A car of m = 1200. kg collides with a tree while traveling 60.0 mph. The collision occurs over a time period of 0.0500 seconds.
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You may know linear momentum is given by P= mass.velocity. Initially car is moving with some velocity so you know initial momentum of the car. Finally it comes to rest i.e final momentum of the car is 0. According to Newton's second law : Force = change in momentum /time. Applying this you'll get answer as 642840N. Hope it helped you. Revert back to me if you have any questions. Please check out the calculation it might be wrong!
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In a 49 s interval, 595 hailstones strike a glass window of an area of 0.954 m at an angle of 25° to the window surface. Each ha
eduard

Average  force on the window: 0.32 N

Explanation:

The average force exerted on the window is given by Newton's second law

F=\frac{\Delta p}{\Delta t}

where

\Delta p is the net change in momentum of the hailstones in a time interval of \Delta t

In order to find the change in momentum, we have to consider only the component of the hailstone's momentum perpendicular to the window, therefore:

p_i =m u sin \theta is the initial momentum of one hailstone, with

m = 7 g = 0.007 kg is the mass

u=4.5 m/s is the initial speed

\theta=25^{\circ} is the angle with the window

The final momentum is

p_f = mv sin \theta

where

v = 4.5 m/s is the final speed (the  collision is elastic so the speed is equal, while the direction changes)

\theta=-25^{\circ} (after the rebound, the direction has changed)

So the change in momentum of 1 hailstone is

\Delta p = mv sin(-25^{\circ})-mu sin(25^{\circ})=-2mu sin(25^{\circ})=-0.0266 kg m/s

We are interested only in the magnitude, so

\Delta p = 0.0266 kg m/s

There are 595 hailstones hitting the window in 49 s, so the total change in momentum is

\Delta p = 595\cdot 0.0266 = 15.8 kg m/s

And therefore, the average force on the window is

F=\frac{\Delta p}{\Delta t}=\frac{15.8}{49}=0.32 N

Learn more about  force:

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brainly.com/question/11292757

brainly.com/question/12978926

#LearnwithBrainly

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