Answer:
because darkness is the absence of light, so that means darkness was there before the light came! :)
Explanation:
Scientific method is a process wherein there is a common end result at the end of each milestone of the research. This is to improve the problem which was intended to be realized at the beginning of conducting or applying scientific method. The feedback loop is the part of the model which allows for continuous improvement of the method, for each result there may be atleast known and observed result analysis which is feedback to a step or the whole process for the betterment of the cycle.
The physical evidence are the silent witnesses against the perpetrators of a crime
The correct option of what the field inspector packages after the crime scene has been photographed is the option;
Reason:
Physical evidence are evidence that originate from inanimate objects or origin that is nonliving, and includes every material or object that serve as an indicator that someone has committed a crime, or that can link a perpetrator to crime
Examples include; Documents, hair, skin, fingerprints, weapons, soil, or fibers
The field inspector, collects the evidence that shows that a crime has been committed which are the physical evidence, after the crime scene has been photographed
Therefore, the correct option is; <u>Physical evidence</u>
Learn more here:
brainly.com/question/16340616
False, agility is more about how fast you are
To solve this problem we will apply the concept related to the heat transferred to a body to reach a certain temperature. This concept is shaped by the energy ratio of a body which is the product of the mass, its specific heat and the change in temperature. For the specific case, it will be the sum of the heat transferred to the Water, the Aluminum and the loss due to latency due to vaporization in the water. That is to say,

Here,
= Mass of Aluminum
= Specific Heat of Aluminum
= Specific Heat of Water
Mass of water
Latent of Vaporization
Replacing,

Converting,


Therefore is required 440.409kCal