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Grace [21]
3 years ago
13

HEELLPPPP All of the following are major parts of the earth's interior except? core asthenosphere stratosphere mantle

Physics
2 answers:
Dmitriy789 [7]3 years ago
8 0
Stratosphere because the stratosphere is a layer of the earth's atmosphere. The fore, the mantle, and the asthenosphere are all major parts of the earth's interior. Hope this helps!
Luden [163]3 years ago
7 0
<span>1. 10x
2. fault line
3. UV Waves
4. through solids and liquids
5. inner core
6. low temperature
7. cinder cone
8. earth's core
9. they are all caused by plate movement
10. inner mantle
11. transverse
12.divergent
13. none of these
14. fault
15. Lithospheric plates
16. foreshocks and aftershocks can happen at the same time
17. stratosphere
18. this question is not complete</span>
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Two uniform solid cylinders, each rotating about its central (longitudinal) axis, have the same mass of 2.88 kg and rotate with
Tanya [424]

Answer:

(a) K_{small}=4839.3J

(b) K_{larger}=17406.4J

Explanation:

Given data

The angular velocity of two cylinders ω=257 rad/s

The mass of the two cylinders m=2.88 kg

The radius of small cylinder r₁=0.319 m

The radius of larger cylinder r₂=0.605 m

For Part (a)

The rotational kinetic energy of the cylinder is given by:

K=\frac{1}{2}Iw^2

Where I is rotational of inertia of solid cylinder about its central axis.

So

K=\frac{1}{2}Iw^2\\ K=\frac{1}{2}(1/2mr^2)w^2

Substitute the given values

So

K_{small}=\frac{1}{4}(2.88kg)(0.319)^2(257rad/s)^2 \\K_{small}=4839.3J

For Part (b)

K=\frac{1}{2}Iw^2\\ K=\frac{1}{2}(1/2mr_{2}^2)w^2

Substitute the given values

K_{larger}=\frac{1}{4}mr_{2}^2w^2\\ K_{larger}=\frac{1}{4}(2.88kg)(0.605m)^2(257rad/s)^2\\ K_{larger}=17406.4J

8 0
3 years ago
A 95kg clock initially at rest on a horizontal floor requires a 560N horizontal force to set it in motion. After the clock is in
miv72 [106K]

Complete Question

A 95 kg clock initially at rest on a horizontal floor requires a 650 N horizontal force to set it in motion. After the clock is in motion, a horizontal force of 560 N keeps it moving with a constant velocity. Find the coefficient of static friction and the coefficient of kinetic friction.

Answer:

The value for static friction is \mu_s =  0.60

The value for static friction is \mu_k =  0.70

Explanation:

From the question we are told that

The mass of the clock is m  =  95 \  kg

The first horizontal force is F _s  =  560 \  N

    The second horizontal force is    F _k  =  650  \  N

Generally the static frictional force is equal to the first  horizontal force

So

     F _s  =  m  *  g  *  \mu_s

=>   560  =  95  *  9.8  *  \mu_s

=>    \mu_s =  0.60

Generally the kinetic frictional force is equal to the second horizontal force

So

      F _k  =  m  *  g  *  \mu_k

      650 =  95  *  9.8  *  \mu_k

     \mu_k =  0.70

3 0
3 years ago
What can you infer about the changes in the environment over time at the mystery fossil dig site? Record your inferences in the
vivado [14]

the fossil informed us about the climatic and geographical changes that occurs in the environment over time.

<h3>What the mystery fossil dig site informed us about environment?</h3>

We can infer about the climate and geographical changes in the environment over time at the mystery fossil dig site because the fossil provides us information about the climatic condition as well as the geography of land when this fossil organism were alive.

So we can conclude that the fossil informed us about the climatic and geographical changes that occurs in the environment over time.

Learn more about fossil here: brainly.com/question/11829803

#SPJ1

4 0
2 years ago
Write down two advantages of parallel combination ​
Simora [160]

Answer:

In parallel combination each appliance gets the full voltage.

If one appliance is switched on/of others are not affected.

The parallel circuit divide the current through the appliances.

In a parallel combination it is very easy to connect or disconnect a new appliance without affecting the working of other appliances.

pls mark me as brainlist

Explanation:

8 0
3 years ago
A car rounds a flat curve and experiences a centripetal force directed toward the center of the curve and perpendicular to the d
Usimov [2.4K]
<h2>Answer:</h2>

If a car is rounding a flat curve, it experiences a centripetal force that pulls it towards the center of the circle it is rotating in.

Now,

The centripetal force can be balanced by the centrifugal force caused due to the acceleration of the body at the high speed which counters the centripetal force and in turn <u>prevents the car from slipping down the curve.</u>

So,

If the car doesn't hit the gas then the <em><u>car will fall down from the curve</u></em> as the Centripetal force will exceed the Centrifugal force of the car.

However, if the car doesn't hit the brake then the <em><u>car will maintain it's position on the flat curve</u></em> track as the centrifugal force will counter the effect of centripetal force directed towards the center.

3 0
3 years ago
Read 2 more answers
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