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3 years ago

HEELLPPPP All of the following are major parts of the earth's interior except? core asthenosphere stratosphere mantle

2 answers:

8 0

Stratosphere because the stratosphere is a layer of the earth's atmosphere. The fore, the mantle, and the asthenosphere are all major parts of the earth's interior. Hope this helps!

Luden [163]3 years ago

7 0

<span>1. 10x
2. fault line
3. UV Waves
4. through solids and liquids
5. inner core
6. low temperature
7. cinder cone
8. earth's core
9. they are all caused by plate movement
10. inner mantle
11. transverse
12.divergent
13. none of these
14. fault
15. Lithospheric plates
16. foreshocks and aftershocks can happen at the same time
17. stratosphere
18. this question is not complete</span>

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Does a photon emitted by a higher-wattage red light bulb have more energy than a photon emitted by a lower-wattage red bulb

Liono4ka [1.6K]

Answer:

The energy of these two photons would be the same as long as their frequencies are the same (same color, assuming that the two bulbs emit at only one wavelength.)

Explanation:

The energy $E$ of a photon is proportional to its frequency $f$ . The constant of proportionality is Planck's Constant, $h$ . This proportionality is known as the Planck-Einstein Relation.

$E = h\, f$ .

The color of a beam of visible light depends on the frequency of the light. Assume that the two bulbs in this question each emits light of only one frequency (rather than a mix of light of different frequencies and colors.) Let $f_{1}$ and $f_{2}$ denote the frequency of the light from each bulb.

If the color of the red light from the two bulbs is the same, those two bulbs must emit light at the same frequency: $f_{1} = f_{2}$ .

Thus, by the Planck-Einstein Relation, the energy of a photon from each bulb would also be the same:

$h\, f_{1} = h\, f_{2}$ .

Note that among these two bulbs, the brighter one appears brighter soley because it emits more photons per unit area in unit time. While the energy of each photon stays the same, the bulb releases more energy by emitting more of these photons.

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2 years ago

The closest stars are 4 light years away from us. How far away must you be from a 854 kHz radio station with power 50.0 kW for t

Lubov Fominskaja [6]

Answer:

The distance from the radio station is 0.28 light years away.

Solution:

As per the question:

Distance, d = 4 ly

Frequency of the radio station, f = 854 kHz = $854\times 10^{3}\ Hz$

Power, P = 50 kW = $50\times 10^{3}\ W$

$I_{p} = 1\ photon/s/m^{2}$

Now,

From the relation:

P = nhf

where

n = no. of photons/second

h = Planck's constant

f = frequency

Now,

$n = \frac{P}{hf} = \frac{50\times 10^{3}}{6.626\times 10^{- 34}\times 854\times 10^{3}} = 8.836\times 10^{31}\ photons/s$

Area of the sphere, A = $4\pi r^{2}$

Now,

Suppose the distance from the radio station be 'r' from where the intensity of the photon is $1\ photon/s/m^{2}$

$I_{p} = \frac{n}{A} = \frac{n}{4\pi r^{2}}$

$1 = \frac{8.836\times 10^{31}}{4\pi r^{2}}$

$r = \sqrt{\frac{8.836\times 10^{31}}{4\pi}} = 2.65\times 10^{15}\ m$

Now,

We know that:

1 ly = $9.4607\times 10^{15}\ m$

Thus

$r = \frac{2.65\times 10^{15}}{9.4607\times 10^{15}} = 0.28\ ly$

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2 years ago

Which data set has the largest range?

astra-53 [7]

Answer:

Line the numbers from smallest to largest the subtract the smallest from the largest numbers.

Explanation:

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2 years ago

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3 years ago

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It has been known for many years that ceramics can conduct electricity. In 2008, scientists found a ceramic material that can co

ollegr [7]

Answer:

The answer is the second option.

Explanation:

This is a higher temperature than Onnes's experiment, and it will allow for a broader use of superconductors.

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3 years ago

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