Answer:
Explanation:
Given
mass of sled =26 kg
coefficient of static friction ![\mu _s=0.096](https://tex.z-dn.net/?f=%5Cmu%20_s%3D0.096)
coefficient of kinetic friction ![\mu _k=0.072](https://tex.z-dn.net/?f=%5Cmu%20_k%3D0.072)
In order to move sled from rest we need to provide a force greater than static friction which is given by
![f_s=\mu mg=0.096\times 26\times 9.8=24.46 N](https://tex.z-dn.net/?f=f_s%3D%5Cmu%20mg%3D0.096%5Ctimes%2026%5Ctimes%209.8%3D24.46%20N)
After Moving Sled kinetic friction comes in to play which is less than static friction
![f_k=\mu _kmg=0.072\times 26\times 9.8=18.34 N](https://tex.z-dn.net/?f=f_k%3D%5Cmu%20_kmg%3D0.072%5Ctimes%2026%5Ctimes%209.8%3D18.34%20N)
therefore minimum force to keep moving sledge at constant velocity is 18.34 N
Answer:
End product of photosynthesis.
Explanation:
Photosynthesis is a process that plants undergo in the manufacture of their food. This is done in the presence of sunlight which is trapped by their coloring pigment called chlorophyll and reactants such as Carbon dioxide and Water.
6CO2+6H2O= C6H12O6+ 6O2
The oxygen gas which is a waste product of photosynthesis is released into the atmosphere and used by animals in respiration.
Answer:
0.0619 m^3
Explanation
number of moles = n = 4.39 mol
pressure = P = 2.25 atm =2.25×1.01×10^5 Pa= 2.27×10^5 Pa
Molar gas constant =R = 8.31 J/(mol K)
Temperature T= 385K
volume of gas = V =?
BY GENERAL GAS LAW WE HAVE
PV = nRT
or V = nRT/P
or V = (4.39×8.31×385)/(2.27×10^5)
V = 0.0618728
V = 0.0619 m^3
The thermosphere is a layer of Earth's atmosphere. The thermosphere is directly above the mesosphere and below the exosphere. It extends from about 90 km (56 miles) to between 500 and 1,000 km (311 to 621 miles) above our planet.