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3 years ago

A 10N force pulls to the right and friction opposes 2N. If the object is 20kg,find the acceleraton.

Physics

2 answers:

zmey [24]3 years ago

8 0

Force = mass * acceleration

10 N - 2 N = 20 kg * acceleration

8 N = 20 kg * acceleration

8 / 20 = acceleration

2/5 m/s^2 = acceleration

tia_tia [17]3 years ago

7 0

Answer:

The acceleration is 0.4 m/s²

Explanation:

Given that,

Force = 10 N

Opposing force = 2 N

Mass of object = 20 kg

We need to calculate the acceleration

Using formula of newton's second law

$F = ma$

Where, F = force

m = mass

a = acceleration

Put the value into the formula

$10N-2N = 20\times a$

$8 N=20\times a$

$a =\dfrac{8}{20}$

$a=0.4\ m/s^2$

Hence, The acceleration is 0.4 m/s²

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8 0

3 years ago

A 1500 kg car traveling east at 40 km/hr turns a corner and speeds up to a velocity of 50 km/hr due north. What is the change in

pantera1 [17]

Answer:

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Explanation:

We shall represent velocity in vector form considering east direction as + ve x axis and north as + y direction.

40 km/h in the east

V₁ = 40 i

V₂ = 50j

momentum p₁ = mV₁

= 1500 X 40 i

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Momentum p₂ = mV₂

= 1500 X 50j

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Change in momentum

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75000j - 60000i

Magnitude of change

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Answer:

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