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2 years ago

A 10N force pulls to the right and friction opposes 2N. If the object is 20kg,find the acceleraton.

Physics

2 answers:

zmey [24]2 years ago

8 0

Force = mass * acceleration

10 N - 2 N = 20 kg * acceleration

8 N = 20 kg * acceleration

8 / 20 = acceleration

2/5 m/s^2 = acceleration

tia_tia [17]2 years ago

7 0

Answer:

The acceleration is 0.4 m/s²

Explanation:

Given that,

Force = 10 N

Opposing force = 2 N

Mass of object = 20 kg

We need to calculate the acceleration

Using formula of newton's second law

$F = ma$

Where, F = force

m = mass

a = acceleration

Put the value into the formula

$10N-2N = 20\times a$

$8 N=20\times a$

$a =\dfrac{8}{20}$

$a=0.4\ m/s^2$

Hence, The acceleration is 0.4 m/s²

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3 years ago

A tube 1.20 m long is closed at one end. A stretched wire is placed near the open end. The wire is 0.350 m long and has a mass o

Ksju [112]

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71.4583 Hz

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L = Length of tube = 1.2 m

l = Length of wire = 0.35 m

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v = Speed of sound in air = 343 m/s

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$f=\frac{v}{4L}\\\Rightarrow f=\frac{343}{4\times 1.2}\\\Rightarrow f=71.4583\ Hz$

The fundamental frequency of the wire and tube is equal so he fundamental frequency of the wire is 71.4583 Hz

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The fundamental frequency of the wire is given by

$f=\frac{1}{2l}\sqrt{\frac{T}{\mu}}\\\Rightarrow f^2=\frac{1}{4l^2}\frac{T}{\mu}\\\Rightarrow T=f^2\mu 4l^2\\\Rightarrow T=71.4583^2\times 0.02714\times 4\times 0.35^2\\\Rightarrow T=67.9064\ N$

The tension in the wire is 67.9064 N

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