suppose that you look into a photometer's eyepiece and the fluorescent disks appear to be equal in intensity. If the distance be
1 answer:
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Given:
density of air at inlet,
density of air at inlet,
Solution:
Now,
(1)
where
A = Area of cross section
= velocity of air at inlet
= velocity of air at outlet
Now, using eqn (1), we get:
= 1.14
% increase in velocity = =114%
which is 14% more
Therefore % increase in velocity is 14%